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emmainna [20.7K]
4 years ago
13

What’s the velocity of a sound wave traveling through air at a temperature of 18°C (64.4°F)?

Physics
2 answers:
GREYUIT [131]4 years ago
7 0

The velocity of a sound wave traveling through air at a temperature of 18°C (64.4°F) is 343m/s.

<u>Explanation : </u>

At normal atmosphere and  pressure, the  velocity of sound wave at increase in temperature is as follows

\mathrm{V}=331 \mathrm{m} / \mathrm{s}+(0.6 \mathrm{m} / \mathrm{s} / \mathrm{c})^{*} \mathrm{T}

where T is the temperature in degrees Celsius.  

Using this equation,  calculate the velocity of a sound wave at 20 degrees Celsius , from the following equations,

\mathrm{V}=331 \mathrm{m} / \mathrm{s}+(0.6 \mathrm{m} / \mathrm{s} / \mathrm{c})^{*} \mathrm{T}

\mathrm{v}=331+(0.6)^{*} 20

\mathrm{v}=331+12

V = 343 m/s

Anna11 [10]4 years ago
4 0

Answer:

342 m/s

Explanation:

The velocity of sound in air is approximated as:

v ≈ 331.4 + 0.6 T

where v is the velocity in m/s and T is the temperature in Celsius.

At T = 18:

v ≈ 331.4 + 0.6 (18)

v ≈ 342.2

The velocity is approximately 342 m/s.

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3 years ago
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En la etiqueta de un bote de fabada de 350 g, leemos que su aporte energético es de 1630 kj por cada 100 g de producto a) La can
fredd [130]

Answer:

(a) 153.37 g

(b) 5705 kJ

Explanation:

(a) To find the amount of bean needed by a man you first calculate the equivalence in beans to 2500kJ

2500kJ*\frac{100g}{1630kJ}=153.37\ g

Thus, 153.37 g has the energy needed by a man that needs 200kJ per day.

(b) The amount of energy per pot of bean is given by:

E=350g*\frac{1630kJ}{100g}\\\\E=5705\ kJ

Thus, the energy is 5705kJ

6 0
3 years ago
The table shows the percentage of carbon dioxide in the Earth’s atmosphere in the years 1800 and 2013. Calculate the difference
Natalka [10]

The difference in the mass of carbon dioxide in 500 kg of air in 2013 compared to 1800 is 0.06 Kg

<h3>Data obtained from the question</h3>
  • Year 1800 percent = 0.028%
  • Year 2013 percent = 0.040%
  • Mass of air = 500 Kg
  • Difference =?

<h3>How to determine the mass of CO₂ in 500 Kg in year 1800</h3>
  • Year 1800 percent = 0.028%
  • Mass of air = 500 Kg
  • Mass of CO₂ =?

Mass = percent × mass of air

Mass of CO₂ = 0.028% × 500

Mass of CO₂ = 0.14 Kg

<h3>How to determine the mass of CO₂ in 500 Kg in year 2013</h3>
  • Year 1800 percent = 0.040%
  • Mass of air = 500 Kg
  • Mass of CO₂ =?

Mass = percent × mass of air

Mass of CO₂ = 0.040% × 500

Mass of CO₂ = 0.2 Kg

<h3>How to determine the difference</h3>
  • Mass of CO₂ in year 1800 = 0.14 Kg
  • Mass of CO₂ in year 2013 = 0.2 Kg
  • Difference =?

Difference = mass in 2013 - mass in 1800

Difference = 0.2 - 0.14

Difference = 0.06 Kg

Learn more about composition:

brainly.com/question/11617445

#SPJ1

7 0
2 years ago
HURRY
motikmotik

Answer:

12

N

in the direction opposite to electric field.

Explanation:

Force on a charged particle

q

due to electric field

E

is given by

→

F

=

q

→

E

|

F

|

=

−

0.06

C

×

200

N

C

=

−

12 N

Here negative indicates that force is in the direction opposite to electric field.

6 0
2 years ago
A square current-carrying loop is placed in a uniform magnetic field B with the plane of the loop parallel to the magnetic field
lina2011 [118]

Answer:

The magnetic field exerts net force and net torque on the loop.

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