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emmainna [20.7K]
3 years ago
13

What’s the velocity of a sound wave traveling through air at a temperature of 18°C (64.4°F)?

Physics
2 answers:
GREYUIT [131]3 years ago
7 0

The velocity of a sound wave traveling through air at a temperature of 18°C (64.4°F) is 343m/s.

<u>Explanation : </u>

At normal atmosphere and  pressure, the  velocity of sound wave at increase in temperature is as follows

\mathrm{V}=331 \mathrm{m} / \mathrm{s}+(0.6 \mathrm{m} / \mathrm{s} / \mathrm{c})^{*} \mathrm{T}

where T is the temperature in degrees Celsius.  

Using this equation,  calculate the velocity of a sound wave at 20 degrees Celsius , from the following equations,

\mathrm{V}=331 \mathrm{m} / \mathrm{s}+(0.6 \mathrm{m} / \mathrm{s} / \mathrm{c})^{*} \mathrm{T}

\mathrm{v}=331+(0.6)^{*} 20

\mathrm{v}=331+12

V = 343 m/s

Anna11 [10]3 years ago
4 0

Answer:

342 m/s

Explanation:

The velocity of sound in air is approximated as:

v ≈ 331.4 + 0.6 T

where v is the velocity in m/s and T is the temperature in Celsius.

At T = 18:

v ≈ 331.4 + 0.6 (18)

v ≈ 342.2

The velocity is approximately 342 m/s.

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GREYUIT [131]

Test:

Performing a Litmus Test

Result:

Litmus paper gives the user a general indication of acidity or alkalinity as it correlates to the shade of red or blue that the paper turns.

  • To test the pH of a substance, dip a strip of litmus paper into the solution or use a dropper or pipette to drip a small amount of solution onto the litmus paper.
  • Blue litmus paper can indicate an acid with a pH between 4 and 5 or lower.
  • Red litmus paper can show a base with a pH greater than 8.
  • If a solution has a pH between 5 and 8, it will show little color change on the litmus paper.
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4 0
3 years ago
Explain how the potential energy of two charged particles depends on the distance between the charged particles and on the magni
maks197457 [2]

Answer:

According to Coulomb's Law, the potential energy of two charged particles is directly proportional to the product of the two charges and inversely proportional to the distance between the charges

Explanation:

According to Coulomb's Law, the potential energy of two charged particles is directly proportional to the product of the two charges and inversely proportional to the distance between the charges.  Since the potential energy  of two charged particles is directly proportional to the product of the two charges, its magnitude increases as the charges of the particles increases. For like charges, the potential energy is positive(the product of the two alike charges must be positive) and since potential energy is inversely proportional to the distance between the charges therefore it decreases as the particles get farther apart . For opposite charges, the potential energy is negative(the product of the two opposite charges must be negative) and since potential energy is inversely proportional to the distance between the two charges, it becomes more negative as the particles get closer together.

8 0
3 years ago
An ammeter with a resistance of 5.0 ohm is connected in series with a 3.0V cell and a lamp rated at 300 mA, 3V. Calculate the cu
Alex

Answer:

I = 0.2 A

Explanation:

Lamp is rated at 300 mA

I_lamp = 0.3 A

Voltage is; V = 3V

Thus; Resistance is given by;

R = V/I

R = 3/0.3

R = 10 ohms

Now, since the ammeter of 5 ohms is connected in series with the lamp. Thus equivalent resistance;

R_eq = 10 + 5

R_eq = 15 ohms

Ammeter current will be;

I = V/R_eq

I = 3/15

I = 0.2 A

3 0
2 years ago
List 5 possible effects of not adhering to standards of measurement
Bond [772]

Explanation:

Without the metric system, we'd have a different International System of Units, the metric system is important because 1mm is 0.1cm, 1 cm is 0.01m, with the imperial system the conversion is tedious. The most important feature of the metric system is its base in scientific fact and repeatable standards of measurement

3 0
3 years ago
Two parallel slits are illuminated by light composed of two wavelengths. One wavelength is λA = 622nm. The other wavelength is λ
Sergio039 [100]

Answer:

\lambda_{B}=414.67 nm

Explanation:

In this question we have given

\lambda_{A}=622nm

we have to find

\lambda_{B}=?

We know that

optical path difference for bright fringe is given as=n\lambda

Here,

n is order of fringe

and optical path difference for dark fringe is given as=(n+.5)\lambda

since the light with wavelength \lambda_{A} produces its third-order bright fringe at the same place where the light with wavelength \lambda_{B} produces its fourth dark fringe  

it means

optical path difference for 3rd order bright fringe= optical path difference for forth order dark fringe

Therefore,

3\lambda_{A}=(4+.5)\lambda_{B}...............(1)

Put value of \lambda_{A} in equation (1)

3 \times 622=(4+.5)\lambda_{B}

1866=4.5\lambda_{B}

\lambda_{B}=414.67 nm

3 0
3 years ago
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