The answer is a. yo-yo dieting
During this process a seed will develop. Fertilization in flowering plants happens through a process called pollination. Pollination occurs when pollen grains from the anther land on stigma, and after fertilization occurs, each ovule develop into a seed. Each seed seed contains a tiny, undeveloped plant called an embryo.
As we sit in a chair, Action force will be only in one direction and that direction would be downward only.
In short, Your Answer would be Option A
Hope this helps!
- Initial velocity=0m/s=u
- Acceleration=a=5.5m/s^2
#8.1
![\\ \sf\longmapsto v=u+at](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20v%3Du%2Bat)
![\\ \sf\longmapsto v=0+5.5(12)](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20v%3D0%2B5.5%2812%29)
![\\ \sf\longmapsto v=66m/s](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20v%3D66m%2Fs)
#8.2
Use third equation of kinematics
![\\ \sf\longmapsto v^2-u^2=2as](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20v%5E2-u%5E2%3D2as)
![\\ \sf\longmapsto s=\dfrac{v^2-u^2}{2a}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20s%3D%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2a%7D)
![\\ \sf\longmapsto s=\dfrac{18^2-0^2}{2(5.5)}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20s%3D%5Cdfrac%7B18%5E2-0%5E2%7D%7B2%285.5%29%7D)
![\\ \sf\longmapsto s=\dfrac{324}{11}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20s%3D%5Cdfrac%7B324%7D%7B11%7D)
![\\ \sf\longmapsto s=29.4m](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20s%3D29.4m)
Answer:
Explanation:
It is given that,
Speed of one quoll around a curve, v = 3.2 m/s (maximum speed)
Radius of the curve, r = 1.4 m
On the curve, the centripetal force is balanced by the frictional force such that the coefficient of frictional is given by :
![\mu=\dfrac{v^2}{rg}](https://tex.z-dn.net/?f=%5Cmu%3D%5Cdfrac%7Bv%5E2%7D%7Brg%7D)
![\mu=\dfrac{(3.2\ m/s)^2}{1.4\ m\times 9.8\ m/s^2}](https://tex.z-dn.net/?f=%5Cmu%3D%5Cdfrac%7B%283.2%5C%20m%2Fs%29%5E2%7D%7B1.4%5C%20m%5Ctimes%209.8%5C%20m%2Fs%5E2%7D)
![\mu=0.74](https://tex.z-dn.net/?f=%5Cmu%3D0.74)
So, the coefficient of static friction between the quoll's feet and the ground in this trial is 0.74. Hence, this is the required solution.