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Dennis_Churaev [7]
3 years ago
14

Please help !!!! I’m taking a quiz

Physics
1 answer:
icang [17]3 years ago
7 0

Answer: 512 and 16

Explanation:

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A vehicle is moving with 20m/s towards the east and another is moving 15m/s towards the west​
just olya [345]

Answer:

5 m/s

Explanation:

Given that,

A vehicle is moving with 20m/s towards the east and another is moving 15m/s towards the west​.

It is assumed to find the resultant velocity of the vehicle. Let east side is positive and west is negative. So,

v=v_1+v_2\\\\=20+(-15)\\\\=5\ m/s

Hence, the resultant velocity of the vehicle is equal to 5 m/s.

6 0
2 years ago
Dos láminas, una de cobre y otra de hierro, se encuentran soldadas y empotradas enuna pared como lo muestra la figura 13. Si las
PolarNik [594]

Answer:

umm i gotta put this in English!!!!!

7 0
3 years ago
How are physical descriptions and physical properties similar
elena55 [62]

They are both used to observe and describe matter.

5 0
3 years ago
Read 2 more answers
If a young protostar with a disk is rotating and shrinking. how much faster is it rotating after its size has decreased by a fac
maks197457 [2]
In this system we have the conservation of angular momentum: L₁ = L₂
We can write L = m·r²·ω

Therefore, we will have:
m₁ · r₁² · ω₁ = m₂ · r₂² · ω₂

The mass stays constant, therefore it cancels out, and we can solve for ω<span>₂:
</span>ω₂ =  (r₁/ r₂)² · ω<span>₁
     
Since we know that r</span>₁ = 4r<span>₂, we get:
</span>ω₂ =  (4)² · ω<span>₁
     = 16 </span>· ω<span>₁

Hence, the protostar will be rotating 16 </span><span>times faster.</span>
5 0
3 years ago
A Michelson interferometer operating at a 400 nm wavelength has a 3.95-cm-long glass cell in one arm. To begin, the air is pumpe
AURORKA [14]

Answer:

55.3

Explanation:

The computation of the number of bright-dark-bright fringe shifts observed is shown below:

\triangle m = \frac{2d}{\lambda} (n - 1)

where

d = 3.95 \times 10^{-2}m

\lambda = 400 \times 10^{-9}m

n = 1.00028

Now placing these values to the above formula

So, the  number of bright-dark-bright fringe shifts observed is

=  \frac{2 \times3.95 \times 10^{-2}m}{400 \times 10^{-9}m} (1.00028 - 1)

= 55.3

We simply applied the above formula so that the number of bright dark bright fringe shifts could come

8 0
3 years ago
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