Answer:
5 m/s
Explanation:
Given that,
A vehicle is moving with 20m/s towards the east and another is moving 15m/s towards the west.
It is assumed to find the resultant velocity of the vehicle. Let east side is positive and west is negative. So,

Hence, the resultant velocity of the vehicle is equal to 5 m/s.
They are both used to observe and describe matter.
In this system we have the conservation of angular momentum: L₁ = L₂
We can write L = m·r²·ω
Therefore, we will have:
m₁ · r₁² · ω₁ = m₂ · r₂² · ω₂
The mass stays constant, therefore it cancels out, and we can solve for ω<span>₂:
</span>ω₂ = (r₁/ r₂)² · ω<span>₁
Since we know that r</span>₁ = 4r<span>₂, we get:
</span>ω₂ = (4)² · ω<span>₁
= 16 </span>· ω<span>₁
Hence, the protostar will be rotating 16 </span><span>times faster.</span>
Answer:
55.3
Explanation:
The computation of the number of bright-dark-bright fringe shifts observed is shown below:

where
d = 

n = 1.00028
Now placing these values to the above formula
So, the number of bright-dark-bright fringe shifts observed is

= 55.3
We simply applied the above formula so that the number of bright dark bright fringe shifts could come