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-Dominant- [34]
2 years ago
15

What is Acceleration?​

Physics
2 answers:
Maru [420]2 years ago
7 0

Answer:

Depends on what are you looking at. All of the following are valid definitions, it just depends on which way you are analizing the problem.

<u>From a kinematics point of view:</u>

Acceleration is, by definition, is a vector quantity that measures the rate of change of the rate of change in position (add brackets if it helps visualizing the idea). This leads to the following different definitions - which are more like means of calculating it

  • the second derivative of position with respect to time a = \ddot x= \frac{d}{dt}({\frac d{dt}} x);
  • the first derivative of velocity with respect to time a = \dot v = \frac d{dt} v.

<u>From a dinamics point of view</u>

Acceleration is the effect of a force applied to a body, and measures the ratio of the force applied to a body of mass m and the mass itself (which is another formulation of Newton second law):

a = \frac Fm

earnstyle [38]2 years ago
5 0

Acceleration is the rate of change of velocity

 

To define acceleration, We need to know more about motion.

Motion: This can be defined as the change in position of a body from one point to another. When an object accelerates, it undergoes motion.

<u>Definition</u>

Acceleration can be defined as the rate of change of velocity. The S.I unit of acceleration is meter-per-squared seconds. (m/s²)

The formula of acceleration is

  • a = (v-u)/t................. Equation 1

⇒ Where:

  • a = acceleration
  • u = initial velocity
  • v = final velocity
  • t = time

Hence, Acceleration is the rate of change of velocity

Learn more about acceleration here: brainly.com/question/605631

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A concert loudspeaker suspended high off the ground emits 34 W of sound power. A small microphone with a 1.0 cm2 area is 44 m fr
rjkz [21]

Answer:

<u>Part A</u>

I = 1.4 mW/m²  

<u>Part B</u>

β = 91.46 dB

Explanation:

<u>Part A</u>

Sound intensity is the power per unit area of sound waves in a direction perpendicular to that area. Sound intensity is also called acoustic intensity.

For a spherical sound wave, the sound intensity is given by;

                                            I = \frac{P}{A}

                                            I = \frac{P}{4\pi r^{2}}

Where;

P is the source of power in watts (W)

I is the intensity of the sound in watt per square meter (W/m2)

r is the distance r away

Given:

P = 34 W,

A = 1.0 cm²

r = 44 m

The sound intensity at the position of the microphone is calculated to be;

                                     I = \frac{34}{4\pi (44)^{2}}

                                     I = \frac{34}{4\pi (44)^{2}}

                                     I = 0.0013975 W/m²

                                 ≈  I = 0.0014 W/m² = 1.4 × 10⁻³ W/m²

                                     I = 1.4 mW/m²

The sound intensity at the position of the microphone is 1.4 mW/m².

<u>Part B</u>

Sound intensity level or acoustic intensity level is the level of the intensity of a sound relative to a reference value.  It is a a logarithmic quantity. It is denoted by β and expressed in nepers, bels, or decibels.

Sound intensity level is calculated as;  

                                    β = 10log_{10}\frac{I}{I_{0}}  dB

Where,

β is the Sound intensity level in decibels (dB)

I is the sound intensity;

I₀ is the reference sound intensity;

By pluging-in, I₀ is 1.0 × 10⁻¹² W/m²

           ∴        β = 10log_{10}\frac{1.4 * 10^{-3} W/m^{2}}{1.0 * 10^{-12} W/m^{2}}

                      β = 10log_{10} (1.4 * 10^{9})

                      β = 91.46 dB

The sound intensity level at the position of the microphone is 91.46 dB.                

4 0
3 years ago
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