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3 years ago

1. Fill in the blanks: For the line 3.x - y = 2, the x-intercept is and the y-intercept is-

Mathematics

1 answer:

Allushta [10]3 years ago

4 0

Answer:

x-intercept: (2/3, 0)

y-intercept: (0, -2)

Step-by-step explanation:

x-intercept: when y = 0

3x - y = 2

3x - 0 = 2

x = 2/3

y-intercept: when x = 0

3x - y = 2

0 - y = 2

y = -2

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Suppose the band is raising money to help offset the cost of a trip. You

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Answer:

y-step explanation:

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3 years ago

Read 2 more answers

If Gabe's Soccer Ball Company is able, due to competitive pressure, to charge $60 for a new soccer ball, while one soccer ball c

Brums [2.3K]

Answer:

Results are below.

Step-by-step explanation:

Giving the following information:

Selling price= $60

Unitary variable cost= $28

Fixed costs= $15,000

First, we need to calculate the average total cost:

Average cost= total cost / number of units

For example, for 1 unit and 10,000 units:

1 unit:

Average cost= 15,028/1 = 15,028

10,000 units:

Average cost= (15,000 + 28*10,000) / 10,000

Average cost= $29.5

Now, we can calculate the break-even point in units:

0= (60*x) - (28*x) - 15,000

x= number of units to break-even

0= 32x - 15,000

15,000/32= x

468.75=x

break-even point in units= 469

For the desired profit of $10,000:

10,000 = (60*x) - (28*x) - 15,000

25,000= 32x

781.25= x

Break-even point= 782 units

Finally, fixed costs dropped by $8,000:

0= 32x - 7,000

x= 7,000/32

x= 218.75

Break-even point= 219

Difference= 250 units

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3 years ago

Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]

Anit [1.1K]

Answer:

The answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

Step-by-step explanation:

$\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}$

Solve the L.H.S part:

$\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]$

After calculating the L.H.S part compare the value with R.H.S:

$\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\$

$\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\$

In equation (i) multiply by 3 and subtract by equation (iii):

$\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to c= - \frac{1}{2}$

put the value of c in equation (i):

$\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\$

In equation (ii) multiply by 3 then subtract by equation (iv):

$\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\$

put the value of d in equation (iv):

$\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2$

The final answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

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3 years ago

Find f(2) given f(x) = -3x^3 + x^2 – 3

aleksley [76]

Answer:

Step-by-step explanation:

f(x) = -3x^3 + x^2 – 3 f(2) means that wherever you see a x, put in a 2.

f(2)= -3(2)^3 + (2)^2 - 3

f(2) = -3*8 + 4 - 3

f(2) = - 24 + 1

f(2) = - 23

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