Answer:
Explanation:
The bulbs becomes dimmer because effective resistance of the circuit increases since the resistance of the circuit in series connection involves adding the individual resistance compared to in parallel connection where the effective resistance = 1 / R1 + 1/R2 = R1 R2 / ( R2 + R1). The brightness remains the same because the lightbulbs must be of the same resistance. Also using ohm's law
V = IR
I = V / R
I is inversely proportional to the current in the circuit so as R, effective resistance of the circuit increases, I, current decreases and vice versa
Hi, thank you for posting your question here at Brainly.
For this problem involving electrostatics, we will use the Coulomb's Law. The equation is written as:
F = k*Q1*Q2/r^2
F is the force between them, which I assume is what you're looking for. Q1 = -26 nC = -26E-9 C; Q2 = +26 nC = -26E-9 ; r = 0.1m ; and k is a constant which is equal to 9E+9 Nm^2/C.
F = (9E+9)(26E-9)(-26E-9)/(0.1)^2
F = -6.084E+32 N
Answer:
Ethyne consists of a triple bond that is most easier to be broken as compared to that of ethyne with a double bond and benzene single bonds. Therefore ethyne is most reactive among the given options.
Explanation:
Answer:
He examined covered and uncovered meat to determine that maggots came from eggs.
In other other words A
Answer:
The time taken is 
Explanation:
From the question we are told that
The speed of first car is 
The speed of second car is 
The initial distance of separation is 
The distance covered by first car is mathematically represented as

Here
is the initial distance which is 0 m/s
and
is the final distance covered which is evaluated as
So


The distance covered by second car is mathematically represented as

Here
is the initial distance which is 119 m
and
is the final distance covered which is evaluated as

Given that the two car are now in the same position we have that

