Complete question:
A uniform electric field is created by two parallel plates separated by a
distance of 0.04 m. What is the magnitude of the electric field established
between the plates if the potential of the first plate is +40V and the second
one is -40V?
Answer:
The magnitude of the electric field established between the plates is 2,000 V/m
Explanation:
Given;
distance between two parallel plates, d = 0.04 m
potential between first and second plate, = +40V and -40V respectively
The magnitude of the electric field established between the plates is calculated as;
E = ΔV / d
where;
ΔV is change in potential between two parallel plates;
d is the distance between the plates
ΔV = V₁ -V₂
ΔV = 40 - (-40)
ΔV = 40 + 40
ΔV = 80 V
E = ΔV / d
E = 80 / 0.04
E = 2,000 V/m
Therefore, the magnitude of the electric field established between the plates is 2,000 V/m
I believe the answer should be the last option. upon interaction, both objects should have the same charge after the electrons are transferred.
The displacement volume in liters is 2.74 liters.
<h3>What is displacement volume?</h3>
Displacement volume is the quantity of solvent that will be displaced by a specified quantity of a solid during dissolution.
It can also be defined as the volume displaced by the piston as it moves between top dead center and bottom dead center in a car engine.
<h3>Displacement volume in liters</h3>
1 liter = 61.02 in³
? = 167 in³
= 167/61.02
= 2.74 liters
Thus, the displacement volume in liters is 2.74 liters.
Learn more about displacement volume here: brainly.com/question/1945909
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In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,
KE1 = KE2
The kinetic energy of the system before the collision is solved below.
KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
KE1 = 6125 g cm²/s²
This value should also be equal to KE2, which can be calculated using the conditions after the collision.
KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)
The value of x from the equation is 17.16 cm/s.
Hence, the answer is 17.16 cm/s.
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