Yes they are what are your options
Answer: Formula is C4H8O. In every branch of line formula there are Carbon atom. Carbon makes 4 bonds so In branch left in which two CH3-groups are attached there are also an Hydrogen aton which is not shown.
Explanation: Molecule is organic, it is classified as aldehyde.
Hydrocarbons contains only Carbon and Hydrogen atoms, Organic molecules can contain also other atoms.
Reactions of aldehydes are reduction to alcoholes or oxidation to carboxylic acids. It can not for a polymer.
<h3>
<u>ANSWER</u> </h3>
4. O²-
<h3>
<u>EXPLANATION</u> </h3>
O²- has 16 electrons while Ne has 18 electrons. O²- is a molecule that has one electron added to each atom, meaning that there are two extra electrons which makes O²- the same electron configuration as of Ne atom.
<h3>
Answer:</h3>
43.27 g Mg
<h3>
Explanation:</h3>
The balanced equation for the reaction between magnesium metal and hydrochloric acid is;
Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)
From the equation;
1 mole of magnesium reacts with 2 moles of HCl
We are given;
3.56 moles of Mg and 3.56 moles of HCl
Using the mole ratio;
3.56 moles of Mg would react with 7.12 moles of HCl, and
3.56 moles of HCl would react with 1.78 moles of Mg
Therefore;
The amount of magnesium was in excess;
Moles of Mg left = 3.56 moles - 1.78 moles
= 1.78 moles
But; 1 mole of Mg = 24.305 g/mol
Therefore;
Mass of magnesium left = 1.78 moles × 24.305 g/mol
= 43.2629 g
= 43.27 g
Thus, the mass of magnesium that remained after the reaction is 43.27 g
Answer: the percent by mass of potassium nitrate is 13.3%
Explanation:
<u>1) Data:</u>
- Mass of solute, m₁ = 45.0 g
- Volume of solvent, V₂ = 295 ml
- density of water, d₂ = 0.997 g/ml
<u>2) Formulae</u>:
- Percent by mass, % = (mass of solute / mass of solution) × 100
- Density, d = mass / volume
<u>3) Solution</u>:
- d = mass / volume ⇒ m₂ = d₂ × V₂ = 0.997 g/ml × 295 ml = 294. g
- mass of solution = m₁ + m₂ = 45.0g + 294. g = 339. g
- % = (45.0 g / 339. g) × 100 = 13.3 %
- The answer has to be reported with 3 significant figures.
