Answer:
The mass of this piece of metal is 37.68g
Explanation:
<u>Step 1:</u> Given data
q = m*ΔT *Cp
⇒with m = mass of the substance
⇒with ΔT = change in temp = final temperature T2 - initial temperature T1
⇒with Cp = specific heat (Cpwater = 4.184J/g °C) (Cpmetam = 0.9J/ g °C)
<u>Step2 : </u>
For this situation : we get for q = m*ΔT *Cp
q(lost, metal) = q(gained, water)
- mass of metal(ΔT)(Cpmetal) = mass of water (ΔT) (Cpwater)
-m (30.6 -100) * 0.9 = 75g *( 30.6 - 23.1) * 4.184J / g °C
-m * (-69.4) * 0.9 = 75g * (7.5) * 4.184J / g °C
-m * (-69.4) *0.9 = 2353.5
-m = 2353.5 / (-69.4 *0.9) = -37.68
m = 37.68g
The mass of this piece of metal is 37.68g
The law of conservation of mass states that mass can neither be created nor destroyed in a chemical reaction. Thus, the amount of matter cannot change.
Answer:
0.01M
Explanation:
Given paramters:
Volume of FeCl₂ = ?
Concentration = 0.945M
Number of molecules of O₂ = 4.32 x 10²¹molecules
Solution:
The balanced reaction equation is given below:
4FeCl₂ + 3O₂ → 2Fe₂O₃ + 4Cl₂
Now, to solve the problem we use mole relationship between the compounds.
We work from the known to the unknown compounds. Here, the known is the oxygen gas because from the given parameters we can estimate the number of moles of the reacting gas.
number of moles of O₂ = 
number of moles of O₂ = 
number of moles of O₂ = 0.007mole
now, from the reaction equation we find the number of moles of the FeCl₂:
3 mole of O₂ reacted with 4 moles of FeCl₂
0.007mole of O₂ reacted with 
= 0.0096mole O₂
Now to find the volume of FeCl₂ we use the expression below;
volume of FeCl₂ = 
= 
= 0.01L
Answer:
1 mole of CO2 and 2 mole H2O will be produced in the reaction.
Explanation:
N:B: I guess it will be 6 moles of O2 not CO2.
Balanced Equation: CH4 + 2O2 --> CO2 + 2H2O
Given,
1 mole CH4
6 moles of O2
According to Stoichiometry,
In the reaction,
2 mole O2 reacts with 1 mole CH4
1 mole O2 reacts with 1/2 mole CH4
∴6 mole O2 reacts with (1/2)*6 mole CH4
= 3 moles of CH4
But, there is only 1 mole CH4 provided. So CH4 is the limiting reagent.
Now,
According to Stoichiometry,
In the reaction,
1 mole CH4 produces 2 moles of H2O
Again,
According to Stoichiometry,
In the reaction,
1 mole CH4 produces 1 mole CO2
So, 1 mole of CO2 and 2 mole H2O will be produced in the reaction.
N:B:[Doing calculation with limiting reagent in problems like these gives you the most accurate answer].
11 L because you just need to use a pie chart
