I'll see what I can do here...
1) Nonmetal
2) Calcium (Ca), chemical element, one of the alkaline-earth metals of Group 2 (IIa) of the periodic table.
3) Hafnium
4) 204.3833 u
5) Not sure what you're asking, but oble gas, any of the seven chemical elements that make up Group 18 (VIIIa) of the periodic table. The elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og)
6) The metalloids; boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), polonium (Po) and astatine (At)
7) The Actinide series contains elements with atomic numbers 89 to 103 and is the third group in the periodic table.
8) 33
9) 88
10) 30
Hope this helps!
<span>You use the Henderson - Hasselbalch equation
pH = pKa + log ([salt]/[acid])
pKa = -log (8.2*10^-5) = 4.081
pH = 4.081 + (0.590/0.190)
pH = 4.081 + log 3.105
pH = 4.081 + 0.49206
pH = 4.573</span>
3.25 C because I said so and energy is green
Answer:
0.682L or 682mL
Use Charles Law of V1/T1 = V2/T2
V1 = 0.6L
T1 = 293K
V2=?
T2= 333K
Explanation:
?
430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.
<h3>What is Molarity?</h3>
- The amount of a substance in a specific volume of solution is known as its molarity (M).
- The number of moles of a solute per liter of a solution is known as molarity.
<h3>Calculation of Required amount of AgCl</h3>
Remember that mol/L is the unit of molarity (M).
We can compute the necessary number of moles of solute by multiplying the concentration by the liters of solution, according to dimensional analysis.
0.75L×4.0M=3.0mol
Then, using the periodic table's molar mass for AgCl, convert from moles to grams:
3.0mol×143.321gmol=429.963g
The final step is to round to the correct significant figure, which in this case is two: 430g.
Hence, 430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.
Learn more about Molarity here:
brainly.com/question/8732513
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