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SOVA2 [1]
4 years ago
5

Which solution has a molality of 0.25m nacl?

Chemistry
2 answers:
Solnce55 [7]4 years ago
5 0

Molality can be expressed by moles of solute over kilograms of solvent. The question asks the molality of 0.25m NaCl. 0.25m NaCl is equal to 0.25 moles of NaCl over 1 kg of water.

vodomira [7]4 years ago
4 0

0.25 moles of NaCl over 1 kg of water

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A chemist adds 405.0mL of a 0.79M sodium carbonate solution to a reaction flask. Calculate the millimoles of sodium carbonate th
Sophie [7]

Answer:

320 mmol

Explanation:

405.0 mL * 1L/1000 mL = 0.4050 L

0.79 M = 0.79 mol/L

0.79 mol/L * 0.4050 L=0.32 mol

0.32 mol * 10^3 mmol/1 mol = 320 mmol

4 0
3 years ago
Which process is an example of a chemical change?
WARRIOR [948]

Answer:

A is the closest thing. You change the composition of the steak. You don't in any of the others.

Explanation:

Usually when you cook something, you are doing something to the composition of the object being cooked. A steak might not be obvious, but boiling an egg should be.

Chopping a tree is something physical. You are removing mass in such a way that the tree will fall. There's nothing chemical about that.

Heating a cup of tea looks like it might be chemical. After all steam is sometimes given off which looks like it is chemical. It's not. The water in the tea is just changing phase.

Drying clothes in a dryer. Again, this looks like something might have changed. After all the mass of the clothes just became less. But all you are doing is separating two masses (leaving one of them behind).

8 0
3 years ago
Read 2 more answers
A saturated solution of Pb(IO3)2 in pure water has a lead ion concentration of 5.0 x 10-5 Molar. What is the Ksp value of Pb(IO3
Orlov [11]

Answer:

Option (E) is correct

Explanation:

Solubility equilibrium of Pb(IO_{3})_{2} is given as follows-

                   Pb(IO_{3})_{2}\rightleftharpoons Pb^{2+}+2IO_{3}^{-}

Hence, if solubility of Pb(IO_{3})_{2} is S (M) then-

                             [Pb^{2+}]=S(M) and [IO_{3}^{-}]=2S(M)

Where species under third bracket represent equilibrium concentrations

So, solubility product of Pb(IO_{3})_{2} , K_{sp}=[Pb^{2+}][IO_{3}^{-}]^{2}

Here, [Pb^{2+}]=S(M)=5.0\times 10^{-5}M

So, [IO_{3}^{-}]=2S(M)=(2\times 5.0\times 10^{-5})M=1.0\times 10^{-4}M

So, K_{sp}=(5.0\times 10^{-5})\times (1.0\times 10^{-4})^{2}=5.0\times 10^{-13}

Hence option (E) is correct

7 0
3 years ago
A. Energy is transferred to different forms
Luden [163]

Answer:

A. Energy is transferred to different forms .

Explanation:

Hello!

In this case, we need to consider the law of conservation of mass and energy which states that mass and energy cannot be neither created nor destroyed, just modified; it means we can rule out B. and C. so far.

Moreover, since D. is actually true for combustion reactions because they are used to provide energy in industrial operations, this is not the concern here because a combustion reaction is not considered.

Therefore the correct option is A. Energy is transferred to different forms as the energy provided by Rose is transferred to the pendulum system .

Best regards!

3 0
3 years ago
n the reaction Mg (s) + 2HCl (aq) H2 (g) + MgCl2 (aq), how many moles of hydrogen gas will be produced from 75.0 milliliters of
Xelga [282]
0.075 L * 1.0 M = 0.075 mol HCl
H2 is half of HCl by the coefficients divide 0.075 by 2 and get 0.0375 mol H2 gas
8 0
4 years ago
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