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Art [367]
3 years ago
7

adding or removing gas to a constant volume what happens to the pressure ? is this a direct or indirect relationship

Chemistry
2 answers:
Elodia [21]3 years ago
5 0
Direct... hope this helps!!!!
posledela3 years ago
3 0
Direct would be your answer

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Calculate the density of an object with a mass of 6.147 and a volume of 9.3 (include units)
Olin [163]
Here is the formula for density:
Density (D) = Mass (M) divided by Volume (V)

So you would do D = 6.147 divided by 9.3

As an as answer you would get: 0.6609677419g/cm^3

Additional information:

The formula for volume is:
V = M divided by D


The formula for Mass is:
M = D times V


I hope this helps :)
5 0
4 years ago
What is the charge of oxygen in Na2O?
Nuetrik [128]

In Na2O, what is the oxidation state of oxygen? In Na2O oxidation state of Na is 1+
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3 years ago
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Carbon is found in all known forms of life. Which statement best describes why carbon is uniquely suited to forming macromolecul
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Carbon and its compound's stability means it is useful in synthesizing organic molecules which are used in the bodies of organisms.
6 0
3 years ago
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PLEASE HELP ME!
harina [27]
The pH scale is used to measure the degree of acidity or alkalinity of a solution. The scale runs from 0 (very acidic solutions can have a negative pH) to 14 (very alkaline solutions can have a pH higher than this), while a neutral liquid such as pure water has a pH of 7. The pH is linked to the concentration of hydrogen ions (H +) in the solution. Diluting an acid or alkali affects the concentration of H +<span> ions in a solution and therefore affects the pH. In this activity, we will investigate how diluting an acid or alkali affects the pH.
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8 0
3 years ago
A certain electrolyte solution contains 1 gram of salt for every 8 grams of sugar and every 200 grams of water. If the sugar to
12345 [234]

Answer:

The resulting solution contains approximately 666 g of water.

Explanation:

In the initial solution we have:

1g salt : 8g sugar : 200g water

This means that the ratios are:

\frac{salt}{sugar}  = \frac{1}{8} \\\\\frac{sugar}{water} = \frac{8}{200} =\frac{1}{25}

In the final solution we have:

5g salt: xg sugar: yg water

The new ratios are:

\frac{salt}{sugar} = \frac{3}{8} \\\\\frac{sugar}{water} = \frac{1}{50}

Now we can calculate the amount of sugar in the final solution:

\frac{salt}{sugar}  = \frac{5}{x} =\frac{3}{8} \\\\X = 13.333 g

Finally, we calculate the amount of water:

\frac{sugar}{water} = \frac{13.333}{y} = \frac{1}{50} \\y = 666.667 g

4 0
3 years ago
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