1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zepelin [54]
2 years ago
9

3.

Chemistry
1 answer:
Vsevolod [243]2 years ago
3 0

Answer:

2 half-lives=0.8

6 half-lives= 0.05

Explanation

Half-lives are constant and always decrease by half, implying that the concentration decreases by half at a consistent rate.

3.2/2= 1.6/2= 0.8 is two half-lives

3.2/2= 1.6/2= 0.8/2= 0.4/2= 0.2/2= 0.1/2=0.05 is six half-lives

You might be interested in
Explain why heat is often used in a laboratory experiment. a. To warm up the laboratory, b. To speed up a reaction
uysha [10]

Answer:

To speed up a reaction

Explanation:

Heat, as well as catalysts, increase the reaction rate of some chemical reactions since they cause the enzymes or reagents in charge of carrying out the transformation to products to act faster and increase their kinetic energy of reaction.

3 0
3 years ago
The total bonding energy for the products of a reaction is 2535 kJ/mol and the bonding energy of the reactants is 1375 kJ/mol. C
omeli [17]

Answer:

1160 kJ/mol

Explanation:

To get the enthalpy of the reaction take ΔH products- ΔH reactants

5 0
3 years ago
A certain substance melts at a temperature of . But if a sample of is prepared with of urea dissolved in it, the sample is found
pshichka [43]

Answer:

2.2 °C/m

Explanation:

It seems the question is incomplete. However, this problem has been found in a web search, with values as follow:

" A certain substance X melts at a temperature of -9.9 °C. But if a 350 g sample of X is prepared with 31.8 g of urea (CH₄N₂O) dissolved in it, the sample is found to have a melting point of -13.2°C instead. Calculate the molal freezing point depression constant of X. Round your answer to 2 significant digits. "

So we use the formula for <em>freezing point depression</em>:

  • ΔTf = Kf * m

In this case, ΔTf = 13.2 - 9.9 = 3.3°C

m is the molality (moles solute/kg solvent)

  • 350 g X ⇒ 350/1000 = 0.35 kg X
  • 31.8 g Urea ÷ 60 g/mol = 0.53 mol Urea

Molality = 0.53 / 0.35 = 1.51 m

So now we have all the required data to <u>solve for Kf</u>:

  • ΔTf = Kf * m
  • 3.3 °C = Kf * 1.51 m
  • Kf = 2.2 °C/m
5 0
3 years ago
Calculate the volume of 0.10 g of titanium (4.51 g/cm³).
Juli2301 [7.4K]

The volume of titanium with mass of 0. 10g and density of 4. 51 g/cm³ is 0. 02 cm³

<h3>What is volume?</h3>

Volume is known to be equal to the mass divided by the density.

It is written thus:

Volume = Mass / density

<h3>How to calculate the volume</h3>

The volume is calculated using the formula:

Volume = mass ÷ density

Given the mass = 0. 10g

Density = 4.51 g/cm³

Substitute the values into the formula

Volume of titanium = 0. 10 ÷ 4.51 = 0. 02 cm³

Thus, the volume of titanium with mass of 0. 10g and density of 4. 51 g/cm³ is 0. 02 cm³

Learn more about volume here:

brainly.com/question/1762479

#SPJ1

4 0
2 years ago
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide dissolved in molten cryolit
natka813 [3]

The given question incomplete, the complete question is:

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite (Na, Alts).re in the reduction of the Al, o, to pure aluminum. Suppose a current of 1800. A is passed through a Hall-Heroult cell for 37.0 seconds. Calculate the mass of pure aluminum produced Be sure your answer has a unit symbol and the correct number of significant digits.

Answer:

The correct answer is 6.2114 grams.

Explanation:

Based on the given question, the value of current or I have given is 1800 amperes, the time given is 37 seconds, and there is a need to find the mass of the pure aluminum generated in the process. Mass or weight can be determined by using Faraday's first law equation, that is, w = MIt/nF.  

Here, M is the atomic mass, w is the weight of the substance deposited, t is time, I is current, n is the number of moles of the electron, and F is the Faraday's constant, which is 96500 C. In the process mentioned in the question, aluminum oxide is reduced to give rise to pure aluminum, and in the process 3 electrons are gained. So, the value of n will be 3. The M or the atomic mass of Al is 27 gm per mole. Now putting the values in the equation we get,  

w = 27*1800*37 / 3*96500

w = 1798200 / 289500

w = 6.2114 grams

Hence, pure aluminum produced in the process is 6.2114 grams.  

7 0
3 years ago
Other questions:
  • When writing 6,020,000 in scientific notation, it is correctly written as: 6.02 x 106 6.02 x 10-6 602. x 106 0.602 x 10-8
    5·2 answers
  • When an atom becomes an ion does its mass number change?
    7·1 answer
  • Because the the individual components of any mixture are not _____ to each other, the composition of those components can vary.
    6·1 answer
  • Complete the passage.
    9·2 answers
  • How many atoms of oxygen are there in one molecule of carbon dioxide, if the chemical formula is CO2?
    8·2 answers
  • What do all substances in the universe have in common?
    9·1 answer
  • Antoine has a 100-gram sample of water in a sealed 1 liter container. He observes that when the water is moved to a sealed 2-lit
    6·2 answers
  • When using the benedict's assay, which color would indicate the most reducing sugar present?
    12·1 answer
  • Predict what would change about your number of sandwiches and your thinking if you had the same 6 pieces of bread and 4 slices o
    6·2 answers
  • Consider the following equilibrium:
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!