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alexgriva [62]
3 years ago
6

Calculate [OH − ], pOH, and pH for each of the following. (Assume that all solutions are at 25°C.) (a) 0.00013 M Ca(OH)2 [OH − ]

2.6*10^Calculate [OH− ], pOH, and pH for (a) 0.00013 M Ca(OH)2 (b) a solution containing 29 g of RbOH per liter (c) a solution containing 150 g of LiOH per liter

Chemistry
1 answer:
MA_775_DIABLO [31]3 years ago
5 0

Answer:

See image attached

Explanation:

The hydroxide ion concentration can easily be calculated from the concentration of the metal hydroxide solutions given as shown in the solution attached. The pH can now be obtained from there using pH+pOH=14. The pH value is always greater than the the pOH value as shown in the solution to the problems attached.

Question (c) contains incorrect data that cannot be used to calculate the required parameters.

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2 years ago
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kvv77 [185]

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4 0
3 years ago
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A 215-g sample of copper metal at some temperature is added to 26.6 g of water. The initial water temperature is 22.22 oC, and t
andrezito [222]

The initial temperature of the copper metal was 27.38 degrees.

Explanation:

Data given:

mass of the copper metal sample = 215 gram

mass of water = 26.6 grams

Initial temperature of water = 22.22 Degrees

Final temperature of water = 24.44 degrees

Specific heat capacity of water = 0.385 J/g°C

initial temperature of copper material , Ti=?

specific heat capacity of water = 4.186 joule/gram °C

from the principle of:

heat lost = heat gained

heat gained by water is given by:

q water = mcΔT

Putting the values in the equation:

qwater = 26.6 x 4.186 x (2.22)

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Now heat lost by metal = heat gained by water

82.77Ti - 2019.71 = 247.19

Ti = 27.38 degrees

8 0
3 years ago
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