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siniylev [52]
2 years ago
10

calculate the concentration of sodium ions made by diluting 45.0 mL of a 0.748 M solution of sodium sulfide to a total volume of

250.0 mL
Chemistry
2 answers:
lesya692 [45]2 years ago
7 0
Use the formula M1V1 = M2V2
45(0.748) = 250(M2)
33.66 = 250(M2)
M2 = 0.135 M
aleksley [76]2 years ago
4 0
C1V1= C2V2
use this formula C1= 0.748 M
V1= 45.0 mL change to L
V2= 250.0 mL again change to L
C2= ?
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IRISSAK [1]

Answer:

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Explanation:

Hello!

In this case, for the undergoing chemical reaction:

ZnO(s)+H_2O(l)\rightarrow Zn(OH)_2

We evaluate the yielded moles of zinc hydroxide by each reactant as shown below:

n_{Zn(OH)_2}^{by ZnO}=35.4gZnO*\frac{1molZnO}{81.38gZnO}*\frac{1molZn(OH)_2}{1molZnO}  =0.435molZn(OH)_2\\\\n_{Zn(OH)_2}^{by H_2O}=6.96gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{1molZn(OH)_2}{1molH_2O}  =0.386molZn(OH)_2

In such a way, since the water yields a smaller amount of zinc hydroxide we conclude it is the limiting reactant so the maximum mass is computed below:

m_{Zn(OH)_2}=0.386molZn(OH)_2*\frac{99.424 gZn(OH)_2}{1molZn(OH)_2} \\\\m_{Zn(OH)_2}=38.4g

Because the water limits the yielded amount of zinc hydroxide.

Best regards!

5 0
3 years ago
How many atoms are there in 2.43 g of calcium?
Evgen [1.6K]

Answer:

Explanation:

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What we must first do is convert the given mass of calcium to moles of calcium, using its molar mass (referring to a periodic table, this is

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