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Combined gas law is
PV/T = K (constant)
P = Pressure
V = Volume
T = Temperature in Kelvin
For two situations, the combined gas law can be applied as,
P₁V₁ / T₁ = P₂V₂ / T₂
P₁ = 3.00 atm P₂ = standard pressure = 1 atm
V₁ = 720.0 mL T₂ = standard temperature = 273 K
T₁ = (273 + 20) K = 293 K
By substituting,
3.00 atm x 720.0 mL / 293 K = 1 atm x V₂ / 273 K
V₂ = 2012.6 mL
hence the volume of gas at stp is 2012.6 mL
Answer:
T₂ = 506.6 K
Explanation:
Given data:
Initial pressure of gas = 25°C (25+273 =298 K)
Initial temperature = 0.500 atm
Final pressure = 0.850 atm
Final temperature = ?
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
0.500 atm / 298 K = 0.850 atm /T₂
T₂ = 0.850 atm × 298 K / 0.500 atm
T₂ = 253.3 atm. K / 0.500 atm
T₂ = 506.6 K
