Answer:
22.715 moles of oxygen are used
Explanation:
Given data:
Number of moles of ethane = 6.49 mol
Number of moles of O₂ required = ?
Solution:
Chemical equation:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
Now we will compare the moles of oxygen with ethane.
C₂H₆ : O₂
2 : 7
6.49 : 7/2×6.49 = 22.715 mol
Thus, 22.715 moles of oxygen are used.
To solve the question you use the following formula:
concentration (1) × volume (1) = concentration (1) × volume (1)
3 M × volume (1) = 1.8 M × 50 mL
volume (1) = (1.8 M × 50 mL) / 3 M = 30 mL
Hydrogen + oxygen --> water
59,1g + x = 528g
528g - 59,1 = x
x = 468,9g
