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lbvjy [14]
4 years ago
15

What name is given to a polymer where all of the substituents (i.e., the R groups) are in the same relative orientation (i.e., o

n the same side of the polymer chain)?
Chemistry
1 answer:
kirza4 [7]4 years ago
5 0

Answer: isotactic

Explanation:

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If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant
Vanyuwa [196]
<h3>Answer:</h3>

              Excess Reagent =  NBr₃

<h3>Solution:</h3>

The Balance Chemical Equation for the reaction of NBr₃ and NaOH is as follow,

                       2 NBr₃ + 3 NaOH   →   N₂ + 3 NaBr + 3 HBrO

Calculating the Limiting Reagent,

According to Balance equation,

               2 moles NBr₃ reacts with  =  3 moles of NaOH

So,

           40 moles of NBr₃ will react with  =  X moles of NaOH

Solving for X,

                       X  =  (40 mol × 3 mol) ÷ 2 mol

                       X  =  60 mol of NaOH

It means 40 moles of NBr₃ requires 60 moles of NaOH, while we are provided with 48 moles of NaOH which is Limited. Therefore, NaOH is the limiting reagent and will control the yield of products. And NBr₃ is in excess as some of it is left due to complete consumption of NaOH.

6 0
3 years ago
Which probe should be used to check the temperature of a chicken breast?
Eddi Din [679]

Answer:

penetration probe

Explanation:

it is a penetration probe

8 0
3 years ago
Given that a 19.00 g milk chocolate bar contains 11.50 g of sugar, calculate the percentage of sugar present in 19.00
Jet001 [13]

Explanation:

check the steps in the attached image

6 0
2 years ago
What is the mass of solute in a 500 mL solution of 0.200 M
Fofino [41]

16.4 grams is the mass of solute in a 500 mL solution of 0.200 M .

sodium phosphate

Explanation:

Given data about sodium phosphate

atomic mass of Na3PO4 = 164 grams/mole

volume of the solution = 500 ml or 0.5 litres

molarity of sodium phosphate solution = 0.200 M

The formula for molarity will be used here to know the mass dissolved in the given volume of the solution:

The formula is

molarity = \frac{number of moles of solute}{volume in litres}

    putting the values in the equation, we get

molarity x volume = number of moles

0.200 X 0.5= number of  moles

number of moles = 0.1 moles

Atomic mass x number of moles = mass

putting the values in the above equation

164 x 0.1 = 16.4 grams

16.4 grams of sodium phosphate is present in 0.5 L of the solution to make a 0.2 M solution.

8 0
3 years ago
What is the pH of a 0.300 M NH₃ solution that has Kb = 1.8 × 10⁻⁵ ? The equation for the dissociation of NH₃ is: NH₃ (aq) + H₂O
nalin [4]

Answer:

11.4

Explanation:

Step 1: Given data

  • Concentration of the base (Cb): 0.300 M
  • Basic dissociation constant (Kb): 1.8 × 10⁻⁵

Step 2: Write the dissociation equation

NH₃(aq) + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq)

Step 3: Calculate the concentration of OH⁻

We will use the following expression.

[OH^{-} ]=\sqrt{Kb \times Cb } = \sqrt{1.8  \times 10^{-5} \times 0.300 } = 2.3 \times 10^{-3} M

Step 4: Calculate the pOH

We will use the following expression.

pOH =-log[OH^{-} ]= -log(2.3 \times 10^{-3} M) = 2.6

Step 5: Calculate the pH

We will use the following expression.

pH+pOH=14\\pH = 14-pOH = 14-2.6 = 11.4

8 0
3 years ago
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