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s344n2d4d5 [400]
3 years ago
7

Why is water a special chemical as a solid versus a liquid?

Chemistry
2 answers:
Andrew [12]3 years ago
7 0

Answer:

it is iceeeeeeeeeee

Explanation:

ice ice baby

Taya2010 [7]3 years ago
4 0

Answer: Solid water, or ice, is less dense than liquid water. Ice is less dense than water because the orientation of hydrogen bonds causes molecules to push farther apart, which lowers the density. ... Because ice is less dense than water, it is able to float at the surface of water.

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Calculate the pH of a solution that is 0.205M benzoic acid and 0.230M sodium benzoate, a salt whose anion is the conjugate base
pickupchik [31]

Answer:

pH = 4.25

Explanation:

A solution composed of a weak acid and its conjugate base is a <em>buffer solution</em>. To calculate the pH of a buffer solution we use the Henderson-Hasselbach equation:

pH = pKa + log ([conjugate base]/[weak acid]

In this case, we have the following data:

[conjugate base] = [sodium benzoate] = 0.230 M

[weak acid] = [benzoic acid] = 0.205 M

The pKa of benzoic acid is 4.2. So, we introduce the data in the equation:

pH = 4.2 + log (0.230 M/0.205 M) = 4.2 + 0.050 = 4.25

4 0
3 years ago
If you are given an ideal gas with pressure (p)259,392.00 pa and temperature (T)=200°c of 1 mole Argon gas in a volume 8.8dm3,ca
GuDViN [60]

Answer: R=4.82436 \frac{Pa. m^{3}}{mol. K}

Explanation:

The Ideal Gas equation is:  

P.V=n.R.T  (1)

Where:  

P is the pressure of the gas  

n the number of moles of gas  

R=8.3144598 \frac{Pa. m^{3}}{mol. K} is the gas constant  

T is the absolute temperature of the gas in Kelvin.

V is the volume

It is important to note that the behavior of a real gas is far from that of an ideal gas, taking into account that <u>an ideal gas is a single hypothetical gas</u>. However, under specific conditions of standard temperature and pressure (T=0\°C=273.15 K and P=1 atm=101,3 kPa) one mole of real gas (especially in noble gases such as Argon) will behave like an ideal gas and the constant R will be 8.3144598 \frac{Pa. m^{3}}{mol. K}.

However, in this case we are not working with standard temperature and pressure, therefore, even if we are working with Argon, the value of R will be far from the constant of the ideal gases.

Having this clarified, let's isolate R from (1):

R=\frac{PV}{nT}  (2)

Where:

P=259392 Pa

n=1 mole

T=200\°C=473.15 K is the absolute temperature of the gas in Kelvin.

V=8.8 dm^{3}=0.0088 m^{3}

R=\frac{(259392 Pa)(0.0088 m^{3})}{(1 mole)(473.15 K)}  (3)

Finally:

R=4.82436 \frac{Pa. m^{3}}{mol. K}  

4 0
3 years ago
Water (2350 g ) is heated until it just begins to boil. If the water absorbs 5.83×105 J of heat in the process, what was the ini
Eva8 [605]

Answer:

40.7062 °C  

Explanation:

Let the initial temperature = x °C

Boiling temperature of water = 100 °C

Using,

Q = m C ×ΔT

Where,  

Q is the heat absorbed in the temperature change from x °C to 100 °C.

C gas is the specific heat of the water = 4.184 J/g  °C

m is the mass of water

ΔT = (100 - x) °C  

Given,

Mass = 2350 g

Q = 5.83 × 10⁵ J

Applying the values as:

Q = m C ×ΔT

5.83 × 10⁵ = 2350 × 4.184 × (100 - x)

<u>x, Initial temperature = 40.7062 °C  </u>

3 0
3 years ago
50 POINTS FOR THE CORRECT ANSWER SOMEONE HELP ME ON THIS QUESTION PLEASE !!!!!!
oee [108]

Answer:

it is positive and it reacts

7 0
3 years ago
Read 2 more answers
Plz help me with this question plzzzzz​
LekaFEV [45]

Answer:

6

Explanation:

Formula: Al2O3

If we require 2Al2O3

                       We divide 2 by 3

Sorry for the shadow of phone and fingers.

 

8 0
3 years ago
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