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WARRIOR [948]
3 years ago
13

Select the correct answer. Which subatomic particle is electrically neutral and found in the nucleus of an atom? A. proton B. ne

utron C. electron D. orbital E.
Chemistry
1 answer:
rodikova [14]3 years ago
8 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

There are 3 subatomic orbitals which are present in an atom:

1. Protons: These sub-atomic particles are positively charged and are found in the nucleus.

2. Electrons: These sub-atomic particles are negatively charged and are found in the orbitals around the nucleus.

3. Neutrons: These sub-atomic particles carry no charge and are known as electrically neutral species. These particles are found in the nucleus.

From the above information, the answer to this question is Option B.

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<span>Made up of particles packed relatively close together, having an indefinite shape but a definite volume</span>
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3 years ago
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4 0
3 years ago
9.05 mol of oxygen gas to g of oxygen gas
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7 0
3 years ago
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6 0
3 years ago
A 25.0 mL aliquot of 0.0680 M EDTA was added to a 59.0 mL solution containing an unknown concentration of V3 . All of the V3 pre
givi [52]

Answer:

\mathbf{0.02 M}

Explanation:

\text{So, from the given question:}

\text{EDTA will make complex with} V^{+3} \text{and the remaining EDTA will react with }Ga^{+3}

\text{Hence, the total concentration of} V^{+3} & Ga^{+3} \text{will be equivalent to EDTA concentration.}

V_{EDTA} = 25 \ mL

V_{V^{+3}} = 59.0 \ mL

V_{Ga^{+3}} = 13.0 \ mL

M_{EDTA} = 0.0680 \ M

M_{V^{+3}} = ???(unknown)

M_{Ga^{+3}} = 0.0400 \ M

V^{+3} + EDTA \to V[EDTA] + EDTA(Excess)  \to^{CoA} \ Ga[EDTA] _{complex}

M_{EDTA} \times V_{EDTA} = ( V_{V^+3}\times M_{V^{+3}}+ V_{Ga^{+3} }\times M_{Ga^{+3}}})

0.0680 \times 25 = (59\times x + 13 \times 0.040) \\ \\ 1.7 = 59x + 0.52\\ \\ 1.7 - 0.52 = 59x \\ \\ 59x = 1.18

x = \dfrac{1.18}{59}

\mathbf{x =0.02 \ M }

5 0
3 years ago
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