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WARRIOR [948]
3 years ago
13

Select the correct answer. Which subatomic particle is electrically neutral and found in the nucleus of an atom? A. proton B. ne

utron C. electron D. orbital E.
Chemistry
1 answer:
rodikova [14]3 years ago
8 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

There are 3 subatomic orbitals which are present in an atom:

1. Protons: These sub-atomic particles are positively charged and are found in the nucleus.

2. Electrons: These sub-atomic particles are negatively charged and are found in the orbitals around the nucleus.

3. Neutrons: These sub-atomic particles carry no charge and are known as electrically neutral species. These particles are found in the nucleus.

From the above information, the answer to this question is Option B.

You might be interested in
Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

6 0
3 years ago
9. If 28.56 g of K2O is produced when 25.00 g K is reactedaccording to the following equation, what is the percent yieldof the r
Mumz [18]

Answer

b. 95%

Explanation

Given:

Mass of K₂O produced (actual yield) = 28.56 g

Mass of K that reacted = 25.00 g

Equation: 4K(s) + O₂(g) → 2K₂0(s)

What to find:

The percent yield of K₂O.

Step-by-step solution:

The first step is to calculate the theoretical yield of K₂O produced.

From the balanced equation, 4 mol K produced 2 mol K₂O

Molar mass of K₂O = 94.20 g/mol)

Molar mass of K = 39.10 g/mol)

This means 4 mol x 39.10 g/mol = 156.40 g K produced 2 mol x 94.20 g/mol = 188.40 g K₂O

So 25.00 g K will produce:

\frac{25.00\text{ }g\text{ }K\times188.40\text{ }g\text{ }K₂O}{156.40\text{ }g\text{ }K}=30.1151\text{ }g\text{ }K₂O

Actual yield of K₂O = 28.56 g

Theoretical yield of k₂O = 30.1151 g

The percent yield for the reaction can now be calculated using the formula below:

\begin{gathered} Percent\text{ }yield=\frac{Actual\text{ }yield}{Theoretical\text{ }yield}\times100\% \\  \\ Percent\text{ }yield=\frac{28.56\text{ }g}{30.1151\text{ }g}\times100\% \\  \\ Percent\text{ }yield=0.9484\times100\% \\  \\ Percent\text{ }yield=94.84\%\approx95\% \end{gathered}

Therefore, the percent yield for the reaction is 95%.

3 0
1 year ago
Someone pls help me I will make you brain
Katena32 [7]

Answer:

it is actually b because i did this i picked b and got it right

Explanation:

4 0
3 years ago
30 g of hydrogen reacts with 120 g of oxygen to form water.How much water is produced?
Rus_ich [418]

According to law of conservation of mass.

In a chemical reaction Mass is neither created nor destroyed.

  • Mass of product =Mass of reactant

#1

Mass of water

\\ \sf\longmapsto 30+120=150g

#2

Mass of sulphur:-

\\ \sf\longmapsto 136.9-111.6=25.3g

6 0
2 years ago
-2(bx-5)=16 slove for b<br>​
Papessa [141]

Explanation:

SADMEP

-2(bx-5) = 16 distribute

-2bx +10 = 16 subtracte

-10 -10

-2bx = 6

divide by -2x (on both sides)

b = -3x

6 0
2 years ago
Read 2 more answers
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