Answer:
37.8 L OF CARBON MONOXIDE IS REQUIRED TO PRODUCE 18.9 L OF NITROGEN.
Explanation:
Equation for the reaction:
2 CO + 2 NO ------> N2 + 2 CO2
2 moles of carbon monoxide reacts with 2 moles of NO to form 1 mole of nitrogen
At standard temperature and pressure, 1 mole of a gas contains 22.4 dm3 volume.
So therefore, we can say:
2 * 22.4 L of CO produces 22.4 L of N2
44.8 L of CO produces 22.4 L of N2
Since, 18.9 L of Nitrogen is produced, the volume of CO needed is:
44.8 L of CO = 22.4 L of N
x L = 18.9 L
x L = 18.9 * 44.8 / 22.4
x L = 18.9 * 2
x = 37.8 L
The volume of Carbon monoxide required to produce 18.9 L of N2 is 37.8 L
<span>c. q = 0.75 g x 0.897 j/g•°c x 22°c</span>
Answer:
The answer is aluminum foil.
The correct answer would be the third option. There would be two atoms that can form hydrogen bonds with the water molecules from the molecule NH2CH2CH2OH. The atoms O and N could make hydrogen bonds with H. Hydrogen bond is an intermolecular force that is a dipole-dipole interaction between a hydrogen and an atom of O, F and N.