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IrinaK [193]
4 years ago
7

This formula equation is unbalanced. P4(s) + Cl2(g) mc030-1.jpg PCl3(l) Which coefficient should be placed in front of PCl3 to b

alance this equation?
Chemistry
1 answer:
Sunny_sXe [5.5K]4 years ago
6 0
To balance a chemical reaction, we need to remember that the number of each atom in the reactant and the product side of the equation should be equal. So, from the reaction <span>P4(s) + Cl2(g) = PCl3(l), there are 4 P atoms in the reactant, the P atoms in the prodcut side should be 4 as well. We balance as follows:

</span> P4(s) + 6Cl2(g) = 4PCl3(l)
<span>
Therefore, the coefficient of the PCl3 should be 4.

</span>
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The attractions that allow molecules of krypton to exist in the solid phase are due to:
OLga [1]

Answer:

4) Van der waals forces

Explanation:

Krypton (Kr) belongs to the noble gas group and has fully filled valence orbitals. In the solid phase, Kr exists as a white solid with a face centered cubic structure.

Intermolecular forces of attraction from the strongest to the weakest include:

Ionic > hydrogen bonding > dipole-dipole > london dispersion

Kr is monoatomic and non-polar. When fully filled (stable) valence orbitals of 2 Kr atoms approach each other in close proximity they experience a repulsive force which prevents the formation of strong bonds. Thus, the only force of attraction in Kr is the long range weak Van Der Waals force also known as the london dispersion force.

7 0
3 years ago
A ball was kicked by a player, the ball was stationary, then it gains a velocity of 5 m/s North. Did the ball accelerate or no?
Tomtit [17]

Answer:

yes

Explanation:

it started moving North 5 m/s

7 0
3 years ago
An ideal gas is brought through an isothermal compression process. The 3.00 mol of gas goes from an initial volume of 261.6×10−6
Eduardwww [97]

Answer : The temperature and the final pressure of the gas is, 586.83 K and 1.046\times 10^{9}atm respectively.

Explanation : Given,

Initial volume of gas = 261.6\times 10^{-6}m^3

Final volume of the gas = 138.2\times 10^{-6}m^3

Heat released = -9340 J

First we have to calculate the temperature of the gas.

According to the question, this is the case of isothermal reversible compression of gas.

As per first law of thermodynamic,

\Delta U=q+w

where,

\Delta U = internal energy

q = heat

w = work done

As we know that, the term internal energy is the depend on the temperature and the process is isothermal that means at constant temperature.

So, at constant temperature the internal energy is equal to zero.

q=-w

Thus, w = -q = 9340 J

The expression used for work done will be,

w=nRT\ln (\frac{V_2}{V_1})

where,

w = work done = 9340 J

n = number of moles of gas  = 3 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas  = ?

V_1 = initial volume of gas

V_2 = final volume of gas

Now put all the given values in the above formula, we get the temperature of the gas.

9340J=3mole\times 8.314J/moleK\times T\times \ln (\frac{261.6\times 10^{-6}m^3}{138.2\times 10^{-6}m^3})

T=586.83K

Now we have to calculate the final pressure of the gas by using ideal gas equation.

PV=nRT

where,

P = final pressure of gas = ?

V = final volume of gas = 138.2\times 10^{-6}m^3=138.2\times 10^{-9}L

T = temperature of gas = 586.83 K

n = number of moles of gas = 3 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get:

P\times (138.2\times 10^{-9}L)=3mole\times (0.0821L.atm/mole.K)\times (586.83K)

P=1.046\times 10^{9}atm

Therefore, the temperature and the final pressure of the gas is, 586.83 K and 1.046\times 10^{9}atm respectively.

6 0
3 years ago
25. To separate benzene from water, a 850 g aqueous solution of benzene is cooled from
Sonja [21]

Answer:

132.94 kilo joules

Explanation:

We are given;

  • Mass of benzene solution is 850 g
  • Temperature change from 95°C to 3° C = 92° C or 92 K

We are required to determine the energy released by the cooling of benzene.

Taking the specific heat capacity of liquid benzene as 1.7 kJ/kg/K

Then we can determine the amount of heat energy released by using the formula;

Heat = Mass × specific heat × change in temperature

        = 0.85 kg × 1.7 kJ/kg/K × 92 K

        = 132.94 kilo joules

Therefore, the heat released by cooling benzene is 132.94 kilo joules

6 0
3 years ago
At a certain temperature the vapor pressure of pure heptane
Amanda [17]

Answer:

215 mm Hg

Explanation:

This is a problem we can solve by utilizing Raoult´s law which states that the partial pressure of component A, P (A) in a solution is given by:

P (A) = X (A ) Pº(A)

where A is the mol fraction of component A, and Pº (A) is the pressure of pure component A.

Now here we have the masses so we can calculate the number of moles  and the mol fraction of component A

n = number of moles = mass / MW

n( C₇H₁₆ ) =  102 g / 100.21 g/mol  = 1.02 mol

n( CHCl₃ ) = 135 g / 119.38 g/mol ) = 1.13 mol

The mol fraction of C₇H₁₆ is given by:

X (C₇H₁₆) =  n( C₇H₁₆ )/ [n( C₇H₁₆ ) + n( CHCl₃ )]

                = 1.02 / ( 1.02 + 1.13 ) = 0.474

Then

P(C₇H₁₆) = X (C₇H₁₆) x (C₇H₁₆)

             = 0.474 x 454 mm Hg = 215 mm Hg

6 0
3 years ago
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