Part d based on your answer to part c, how many bonding electrons and lone pair electrons (nonbonding electrons) are there in th
e lewis structure of hcn?
1 answer:
The Lewis Structure of HCN is shown below,
Number of Bonding Electrons:
In HCN Hydrogen is bonded to Carbon through single bond and Nitrogen is bonded to Carbon through Triple Bond. Single bond is formed by two bonding electrons, while, triple bond is formed by six bonding electrons, Hence,
Number of Bonding Electrons = 8
Number of Non-Bonding Electrons:
In HCN there is only one lone pair of electron present on Nitrogen atom which is not taking part in bonding. Hence,
Number of Non-Bonding Electrons = 2
Result:
Number of Bonding Electrons = 8
Number of Non-Bonding Electrons = 2
Number of Bonding Electrons:
In HCN Hydrogen is bonded to Carbon through single bond and Nitrogen is bonded to Carbon through Triple Bond. Single bond is formed by two bonding electrons, while, triple bond is formed by six bonding electrons, Hence,
Number of Bonding Electrons = 8
Number of Non-Bonding Electrons:
In HCN there is only one lone pair of electron present on Nitrogen atom which is not taking part in bonding. Hence,
Number of Non-Bonding Electrons = 2
Result:
Number of Bonding Electrons = 8
Number of Non-Bonding Electrons = 2
You might be interested in
Answer:
the volume occupied by 3.0 g of the gas is 16.8 L.
Explanation:
Given;
initial reacting mass of the helium gas, m₁ = 4.0 g
volume occupied by the helium gas, V = 22.4 L
pressure of the gas, P = 1 .0 atm
temperature of the gas, T = 0⁰C = 273 K
atomic mass of helium gas, M = 4.0 g/mol
initial number of moles of the gas is calculated as follows;
The number of moles of the gas when the reacting mass is 3.0 g;
m₂ = 3.0 g
The volume of the gas at 0.75 mol is determined using ideal gas law;
PV = nRT
Therefore, the volume occupied by 3.0 g of the gas is 16.8 L.