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notsponge [240]
3 years ago
14

Joshua hooks a rubber band between his thumb and forefinger. He moves his fingers apart, stretching the rubber band. With a quic

k, sudden motion, he bends his thumb forward so that the rubber band slips off. What happens next?
Chemistry
1 answer:
soldi70 [24.7K]3 years ago
3 0

Answer:

The elastic potential energy stored in the stretched rubber band changes to kinetic energy.

Explanation:

Joshua hooks a rubber band between his thumb and forefinger. He moves his fingers apart, stretching the rubber band---- Here potential Energy is stored which is an energy that the rubber band has because of its position and it's potential to be converted into kinetic energy.

With a quick, sudden motion, he bends his thumb forward so that the rubber band slips off----The elastic potential energy stored in the stretched rubber band will change to kinetic energy, which is the Energy in Motion and work needed to accelerate the rubber band from rest to its stated or new position.

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(a) The speed of light in the unknown substance is determined 1.82 x 10⁸ m/s.

(b) The light will bend away from the normal since speed of light in air is not equal to speed of light in the substance.

<h3>What is the speed of light?</h3>

The speed of light passing from air into the substance is calculated as follows;

refractive index = speed of light in air / speed of light in the substance

speed of light in the substance = speed of light in air/refractive index

speed of light in the substance = (3 x 10⁸) / (1.65)

speed of light in the substance = 1.82 x 10⁸ m/s

Thus, the light will bend away from the normal since speed of light in air is not equal to speed of light in the substance.

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Calculate the mass of Octane needed to release 6.20 mol Co2
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The combustion reaction of octane is as follow,

                           C₈H₁₈  +  25/2 O₂     →     8 CO₂  +  9 H₂O

According to balance equation,

8 moles of CO₂ are released when  =  114.23 g (1 mole) Octane is reacted

So,

      6.20 moles of CO₂ will release when  =  X g of Octane is reacted

Solving for X,
                                     X  =  (114.23 g × 6.20 mol) ÷ 8 mol

                                     X  =  88.52 g of Octane
Result:
           88.52 g of Octane is needed to release 6.20 mol CO₂.
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