Question

You are asked to calibrate a 25 mL volumetric pipet. You determine that the temperature of your distilled water is exactly 21.5 degrees Celsius. You carefully determined the mass of a clean dry beaker and found that it was 57.5348 g. You pulled water up to the mark and transferred this to the beaker and found that the new mass was 81.3743 g. What is the actual volume of the pipet?

Answer 1

Answer:

The actual volume of pipet is 23.8901 mL

Explanation:

The formula for the density of water can be used to calculate the volume of water transferred. For which, let us first calculate the mass of water transferred by taking the difference of mass of beaker.

Initial mass of the dry beaker:

initial mass of beaker (dry) = 57.5348 g

Mass of the water:

mass of the water  = final mass of the beaker - initial mass of the beaker

mass of the  water = 81.3743 - 57.5348

mass of the water  = 23.8395 g

The density of water at 21.5°C is 0.997882 g/mL

From the above data,

$Density = \frac{Mass (g)}{Volume (mL)}$

$0.997882 = \frac{23.8395}{Volume (mL)}\\ \\ Volume= \frac{23.8395}{0.997882}\\ \\ Volume=23.8901 mL$

The above calculations show that the volume transferred by pipet is 23.8901 mL.