<span>Northwest is 45 degrees north of west. If a car travels a distance x miles northwest, its northerly component gains x/sqrt(2) miles and its easterly component LOSES xsqrt(2)/ miles.
Resultant height is h = 4500 + 100x/sqrt(2) - 75x/sqrt(2) = [25/sqrt(2)]x + 4500
dh/dt = [25/sqrt(2)]dx/dt = [25/sqrt(2)]v </span>
Solving the complex number, we get the value of the missing value that is ‘a’ = -6
We have been given the expression as
|a – i| = √37 (1)
Which is an expression of complex number. The general expression of complex number is given as
z = x + iy
where x is the real part and iy is the imaginary part
To find the modulus value, the formula is given by,
|z| = |x + iy|
|z| = √[(real part)2 + (imaginary part)2]
|z| = √(x2 + y2)
According to the question, |z| = √37 (2)
Equating equation (1) and (2), we get
√(a2 + 1) = √37
(a2 + 1) = 37
a2 = 37 – 1
a2 = 36
a = √36
a = ±6
Now value of a can be 6 or -6. We have been given that the modulus is in third quadrant.
Hence the value will be negative. Therefore, the missing value will be -6.
Learn more about complex number here : brainly.com/question/5564133
#SPJ9
Answer:
1. Can be Paired or Not Paired
2. Paired
3. Not Paired
Step-by-step explanation:
Two sets of observations are paired if each observation in one set has a special correspondence or connection with exactly one observation in the other data set.
1. Can be Paired or Not paired
Reason -
We might look at testing the difference of means using a two sample t-test. However, we may also try running a paired t-test.
But its used in cases where the observations are usually from the same populations at different times or through different sources etc.
Hence can't conclude that it is paired or not paired.
2. Paired
Reason -
Each record is a price of the same item from different stores.
3. Not paired
Reason -
This is again a case of testing the difference of means of two-samples (2 independent samples precisely) that are not paired.
Answer:
A. 0.9510
B. 0.0480
C. 0.0490
D. No, I would not feel comfortable accepting the shipment if one item was found defective, because the probability is quite small to obtain 1 or more defective items.
