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2 years ago

Simplify 5^2•(4+2^3)

Mathematics

1 answer:

Marta_Voda [28]2 years ago

3 0

Remember to follow PEMDAS, and left -> right rule.

First, solve the Parenthesis:

(4 + 2^3)

Solve the exponent.

2^3 = 2 x 2 x 2 = 4 x 2 = 8

4 + 8 = 12

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(5^2) x (12)

5^2 = 5 x 5 = 25

25 x 12

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Multiply

25 x 12 = 300

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300 is your answer

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<em>~Rise Above the Ordinary</em>

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I need help im gonna post 3 more different questions pls answer them.

Arisa [49]

Answer:

Step-by-step explanation:

x³ - (3 + x)²

4³ - (3 + 4)²

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3 years ago

Given that tan θ ≈ −0.087, where 3 2 π < θ < 2 , π find the values of sin θ and cos θ.

elena-s [515]

Answer:

sin θ ≈ -0.08667
cos θ ≈ 0.99624

Step-by-step explanation:

Straightforward use of the inverse tangent function of a calculator will tell you θ ≈ -0.08678 radians. This is an angle in the 4th quadrant, where your restriction on θ places it. (To comply with the restriction, you would need to consider the angle value to be 2π-0.08678 radians. The trig values for this angle are the same as the trig values for -0.08678 radians.)

Likewise, straightforward use of the calculator to find the other function values gives ...

sin(-0.08678 radians) ≈ -0.08667

cos(-0.08678 radians) ≈ 0.99624

_____

<em>Note on inverse tangent</em>

Depending on the mode setting of your calculator, the arctan or tan⁻¹ function may give you a value in degrees, not radians. That doesn't matter for this problem. sin(arctan(-0.087)) is the same whether the angle is degrees or radians, as long as you don't change the mode in the middle of the computation.

We have shown radians in the above answer because the restriction on the angle is written in terms of radians.

_____

<em>Alternate solution</em>

The relationship between tan and sin and cos in the 4th quadrant is ...

$\cos{\theta}=\dfrac{1}{\sqrt{1+\tan^2{\theta}}}\\\\\sin{\theta}=\dfrac{\tan{\theta}}{\sqrt{1+\tan^2{\theta}}}$

That is, the cosine is positive, and the sign of the sine matches that of the tangent.

This more complicated computation gives the same result as above.

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3 years ago

How can i differentiate this equation?

Dmitry_Shevchenko [17]

$\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}$

$\bf\cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{ \frac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2x\sqrt{x}}$

$\bf \cfrac{dy}{dx}=\cfrac{(4x-10)2x~~-~~(2x^2-10x)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~(2x^2-10x)}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~2x^2+10x}{2x\sqrt{x}} \implies \cfrac{dy}{dx}=\cfrac{6x^2-10x}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2x(3x-5)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{3x-5}{\sqrt{x}}$

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3 years ago

Which sentence from the passage tells the reader how the setting has affected the narrator?

allochka39001 [22]

Answer:

The setting has affected the narrator because it tells you where it's going to take place CAN I HAVE BRAINLIEST SO I CAN BE VIRTUSSO

Step-by-step explanation:

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3 years ago

Can jack built 1/5 of a shed in the same time that kyle can build 5/8 of shed,

Helen [10]

<h3>Answer: 3/10 of a shed</h3>

=============================================================

Explanation:

Let's say the shed comes in 40 equal pieces. Each piece takes the same amount of time to assemble. Why am I picking 40? Because 8*5 = 40.

This will allow us to rewrite the fractions with a common denominator.

1/5 = 8/40 .... multiply top and bottom by 8
5/8 = 25/40 .... multiply top and bottom by 5

So Jack can build 8/40 of the shed in the same amount of time Kyle can build 25/40 of the shed.

Instead of writing fractions (which honestly are a pain to deal with), I'm going to write "8 pieces" and "25 pieces" to represent "8/40" and "25/40" respectively. Just keep in mind that there are 40 pieces total.

So again, Jack can assemble 8 pieces in the time it takes Kyle to assemble 25 pieces.

---------------

The ultimate goal is to have Kyle assemble 40 pieces while Jack puts together some unknown number of pieces (some number between 8 and 40). Let's say it's x.

We can then form this proportion

$\frac{\text{Jack's initial 8 pieces}}{\text{x pieces}}=\frac{\text{Kyle's initial 25 pieces}}{\text{goal of 40 pieces}}$

which simplifies or cleans up to

5/x = 25/40

-----------------

Let's solve for x using cross multiplication

8/x = 25/40

8*40 = x*25

320 = 25x

25x = 320

x = 320/25

x = 12.8

So in the time it takes Kyle to assemble all 40 pieces, Jack can put together 12.8 pieces of the shed. However, we can't have Jack put together some fractional piece, because each "piece" is as small as it gets. We can't get any smaller. It would be like saying a fractional part of an atom or a lego block.

So we'll round 12.8 down to 12.

Jack can assemble 12 pieces in the time it takes Kyle to assemble 40 pieces.

Let's then convert this back to fraction form

12 pieces = 12/40 of a shed = 3/10 of a shed.

8 0

2 years ago