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Digiron [165]
3 years ago
6

Simplify 5^2•(4+2^3)

Mathematics
1 answer:
Marta_Voda [28]3 years ago
3 0

Remember to follow PEMDAS, and left -> right rule.

First, solve the Parenthesis:

(4 + 2^3)

Solve the exponent.

2^3 = 2 x 2 x 2 = 4 x 2 = 8

4 + 8 = 12

_______________________________________________________________

(5^2) x (12)

5^2 = 5 x 5 = 25

25 x 12

_______________________________________________________________

Multiply

25 x 12 = 300

________________________________________________________________

300 is your answer

________________________________________________________________

<em>~Rise Above the Ordinary</em>

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Amanda's computer weighs 56 ounces. how many pounds does it weigh?
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Which statements are true about the ordered pair (−1, 5) and the system of equations?
Rudiy27
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Let's check whether (–1, 5) makes the equations true.
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Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point. (2, 3)
lozanna [386]
Standard equation of a circle: <em>(x-h)² + (y-k)² = r²</em> where <em>(h, k)</em> is the center and <em>r </em>is the radius. In the case of our equation here, <em>(x-5)² + (y+3)² = 25</em>, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.

We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.

Distance = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Distance = \sqrt{(-3-3)^2+(5-2)^2}

Distance = \sqrt{(-6)^2+3^2}

Distance = \sqrt{36+9}

Distance = \sqrt{45}\approx6.7082

6.7082>5,\ so\ (2,3)\ is\ on\ the\ \boxed{exterior}
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3 years ago
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