As a red of recent weather activity, there’s less water available for human consumption. Which blome is affected by the most by
1 answer:
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Answer:
Explanation:
The amplitude of the oscillation under SHM will be .5 m and the equation of
SHM can be written as follows
x = .5 sin(ωt + π/2) , here the initial phase is π/2 because when t = 0 , x = A ( amplitude) , ω is angular frequency.
x = .5 cosωt
given , when t = .2 s , x = .35 m
.35 = .5 cos ωt
ωt = .79
ω = .79 / .20
= 3.95 rad /s
period of oscillation
T = 2π / ω
= 2 x 3.14 / 3.95
= 1.6 s
b )
ω =
ω² = k / m
k = ω² x m
= 3.95² x .6
= 9.36 N/s
c )
v = ω
At t = .2 , x = .35
v = 3.95
= 3.95 x .357
= 1.41 m/ s
d )
Acceleration at x
a = ω² x
= 3.95 x .35
= 1.3825 m s⁻²
Answer:
3.08m/s²
Explanation:
Given parameters:
Radius = 20m
Tangential velocity = 7.85m/s
Unknown:
Centripetal acceleration = ?
Solution:
Centripetal acceleration is the acceleration of a body along a circular path.
it is mathematically given as;
a =
v is the tangential velocity
r is the radius
a = = 3.08m/s²
Explanation:
It is given that, the water from a fire hose follows a path described by equation :
........(1)
The x component of constant velocity,
We need to find the resultant velocity at the point (2,3).
Let and
Differentiating equation (1) wrt t as,
When x = 2 and
So,
Resultant velocity,
v = 6.4 m/s
So, the resultant velocity at point (2,3) is 6.4 m/s. Hence, this is the required solution.