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3 years ago

Is 400 pints greater or lesser than 100 gallons

Mathematics

2 answers:

adoni [48]3 years ago

7 0

100 galons is more than 400 pints

larisa [96]3 years ago

3 0

The answer is greater than

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Malik earned $2,344.55 fixing computers. He charged $35.50 per hour. Which expression does NOT use appropriate compatible number

Mademuasel [1]

I will say b 2,400 and some else

3 0

3 years ago

What is the distance between points v (3,3) and w (-2,-3) round to the nearest tenth if necessary

Vinil7 [7]

Answer:

7.81 u

Step-by-step explanation:

<u>Given :- </u>

Two points (3,3) and (-2,-3) is given to us.

And we need to find out the distance between the two points . So , here we can use the distance formula to find out the distance. As,

$:\implies$ D = √{(x2-x1)² + (y2-y1)²}

$:\implies$ D =√[ (3+2)² +(-3-3)²]

$:\implies$ D =√[ 5² +6²]

$:\implies$ D =√[ 25 +36]

$:\implies$ D = 61

$:\implies$ D = 7.81

<h3>Hence the distance between the two points is 7.81 units .</h3>

6 0

3 years ago

If I got 15 credits in i need 24 to graduate how many more i need

Olegator [25]

Step-by-step explanation:

I would have 9 to graduate

8 0

3 years ago

Read 2 more answers

50 POINTS PLZ HELP

Brums [2.3K]

Answer:

Move it to 2 place to the right

Step-by-step explanation:

4.003×100

=400.3

It can be observed that the dot in front of 4 has been shifted in two times to the front giving us 400.3

But in the case of division,it will be two places to the left...

I hope you understand

3 0

3 years ago

Read 2 more answers

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago