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3 years ago

Round to four significant figures 0.00238866

Chemistry

1 answer:

mixas84 [53]3 years ago

6 0

0.0024 Is it rounded to four significant figures

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0.509g sample pure platinumetal was reacted with HCl to firm O.889g of platinum and chlorine. what is the percent by mass of pla

stepan [7]

Platinum plus chlorine equals 0.889 grams whereas the platinum alone is 0.509grams so 0.509/0.889grams = 57% of the mass of the platinum plus chlorine. The chlorine would be 0.889-0.509=0.38 grams. The chlorine would make up about 42.7% of the total mass in grams.

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3 years ago

What are some unique properties about ice that differ from liquid water to water vapor

Svetradugi [14.3K]

some unique properties about ice that differ from liquid water to water vapor are that it is a solid, not a liquid or gas. It also expands.

7 0

4 years ago

Read 2 more answers

When 28242 J are transferred to water sample, its temperature increases 18⁰C to 63⁰C. Determine the mass of the water sample.

ivanzaharov [21]

Answer:

149.79

Explanation:

Formula

Joules = m * c * delta (t)

Givens

J = 28242

m = ?

c = 4.19

Δt = 63 - 18 = 45

Solution

28242 = m * 4.19 * 45

28242 = m * 188.55

m = 28242 / 188.55

m = 149.79

8 0

3 years ago

The following anions can be separated by precipitation as silver salts: Cl- , Br- , I- , CrO4 2-. If Ag is added to a solution c

dalvyx [7]

Answer:

AgI, AgBr, AgCl and Ag₂CrO₄

Explanation:

Ksp (product solubility constant) is defined as the equilibrium constant of the general reaction:

XₐYₙ(s) → aXⁿ⁺(aq) + nYᵃ⁻(aq)

Where X is cation and Y is anion.

Ksp = [aXⁿ⁺]ᵃ [nYᵃ⁻]ⁿ

The presence of XₐYₙ(s) produce ax moles of aXⁿ⁺ and nx moles of Yᵃ⁻. Where X is the solubility of the compound.

Replacing in Ksp:

Ksp = [ax]ᵃ [nx]ⁿ

Solving for x, Solubility (S) is defined as:

$S = \sqrt[n+a]{\frac{Ksp}{a^{a} n^n} }$

For AgCl, Ag₂CrO₄, AgBr and AgI solubilities are:

$S = \sqrt[2]{\frac{1.8x10^{-10}}{1} }$ = 1.34x10⁻⁵M

$S = \sqrt[3]{\frac{1.1x10^{-12}}{4} }$ = 6.50x10⁻⁵M

$S = \sqrt[2]{\frac{5.4x10^{-13}}{1} }$ = 7.35x10⁻⁷M

$S = \sqrt[2]{\frac{8.5^{-17}}{1} }$ = 9.22x10⁻⁹M

The lower solubility is the first compound in precipitate, thus, order of precipitation is:

AgI, AgBr, AgCl and Ag₂CrO₄

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3 years ago

Which type of solid can be described by the unknown solid if it has the properties listed in the table below?

Bingel [31]

Answer:

Ionic

Explanation:

8 0

3 years ago