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3 years ago

QUESTION 2

Chemistry

1 answer:

alina1380 [7]3 years ago

8 0

Answer:

Explanation:

Mutualism is A symbiotic relationship between two species in which both partners benefit

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Why is Darwins theory of evolution by natural selection not just a theory

Mamont248 [21]

Answer:

it talks about reality ..how animals and human came to existence and how they disappear ..this is evolution

the environment chooses those who best fit in it and others are selected ..as in die ..this is referred to as natural selection

and further in this theory .animals produce off springs who survive in the environment

4 0

3 years ago

According to Coulomb’s law, what will happen to the electric force between

Deffense [45]

Answer:

C. Fe will stay positive and increase in magnitude.

Explanation:

Coulomb's law states that the force of attraction of repulsion between two charged particles is directly proportional to the magnitude of their charges and inversely proportional to the square of the distance of separation between them.

This means that if the size of the charges are large, the force acting on them will be large as well. Also if the distance between the two charges increases the force decreases. However, the force increases when the distance of separation decreases.

Like charges repel, therefore, two negative charges brought together will repel each other, and the distance between the two charges decreases, the force will increase in magnitude. Forces of repulsion are considered positive, therefore, the force, Fe, will stay positive and increase in magnitude.

8 0

3 years ago

A cylinder contains 3.1 L of oxygen at 300 K and 2.7 atm. The gas is heated, causing a piston in the cylinder to move outward. T

zubka84 [21]

Answer: The moles of gas present in the cylinder is 0.34 moles.

Explanation:

Given: $P_{1}$ = 2.7 atm, $V_{1}$ = 3.1 L, $T_{1}$ = 300 K

$P_{2}$ = ?, $V_{2}$ = 9.4 L, $T_{2}$ = 610 K

Formula used to calculate the final temperature is as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Substitute the values into above formula as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{2.7 atm \times 3.1 L}{300 K} = \frac{P_{2} \times 9.4 L}{610 K}\\P_{2} = \frac{5105.7}{2820} atm\\= 1.81 atm$

Now, moles present upon heating the cylinder are as follows.

$P_{2}V_{2} = n_{2}RT_{2}\\1.81 atm \times 9.4 L = n_{2} \times 0.0821 L atm/mol K \times 610 K\\n_{2} = \frac{17.014}{50.081} mol\\= 0.34 mol$

Thus, we can conclude that moles of gas present in the cylinder is 0.34 moles.

6 0

3 years ago

What are electrolytes

Alex777 [14]

An electrolyte is a substance that produces an electrically conducting solution when dissolved in a polar solvent, such as water. The dissolved electrolyte separates into cations and anions, which disperse uniformly through the solvent. Electrically, such a solution is neutral.

Hope this helps!!
:)

3 0

3 years ago

Calculate [H3O+] and [OH−] for each of the following solutions at 25 ∘C given the pH. pH= 8.74, pH= 11.38, pH= 2.81

Gnom [1K]

Answer:

Explanation:

Given parameters;

pH = 8.74

pH = 11.38

pH = 2.81

Unknown:

concentration of hydrogen ion and hydroxyl ion for each solution = ?

Solution

The pH of any solution is a convenient scale for measuring the hydrogen ion concentration of any solution.

It is graduated from 1 to 14

pH = -log[H₃O⁺]

pOH = -log[OH⁻]

pH + pOH = 14

Now let us solve;

pH = 8.74

since pH = -log[H₃O⁺]

8.74 = -log[H₃O⁺]

[H₃O⁺] = 10⁻ $^{8.74}$

[H₃O⁺] = 1.82 x 10⁻⁹mol dm³

pH + pOH = 14

pOH = 14 - 8.74

pOH = 5.26

pOH = -log[OH⁻]

5.26 = -log[OH⁻]

[OH⁻] = 10 $^{-5.26}$

[OH⁻] = 5.5 x 10⁻⁶mol dm³

2. pH = 11.38

since pH = -log[H₃O⁺]

11.38 = -log[H₃O⁺]

[H₃O⁺] = 10⁻ $^{11.38}$

[H₃O⁺] = 4.17 x 10⁻¹² mol dm³

pH + pOH = 14

pOH = 14 - 11.38

pOH = 2.62

pOH = -log[OH⁻]

2.62 = -log[OH⁻]

[OH⁻] = 10 $^{-2.62}$

[OH⁻] =2.4 x 10⁻³mol dm³

3. pH = 2.81

since pH = -log[H₃O⁺]

2.81 = -log[H₃O⁺]

[H₃O⁺] = 10⁻ $^{2.81}$

[H₃O⁺] = 1.55 x 10⁻³ mol dm³

pH + pOH = 14

pOH = 14 - 2.81

pOH = 11.19

pOH = -log[OH⁻]

11.19 = -log[OH⁻]

[OH⁻] = 10 $^{-11.19}$

[OH⁻] =6.46 x 10⁻¹²mol dm³

5 0

4 years ago