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kondor19780726 [428]
4 years ago
10

What are the endpoint coordinates for the midsegment of △JKL that is parallel to line JL?

Mathematics
2 answers:
shepuryov [24]4 years ago
5 0

Answer:

<h2> (2.5, 2.5) and (2,0)</h2>

Step-by-step explanation:

The midsegment of △JKL that is parallel to line JL, it's a segment that begins at JK side and ends at LK side. This means we just need to find the coordinates of JK and LK midpoints.

The formula for midpoints is

m=(\frac{x_{1}+x_{2} }{2} ,\frac{y_{1}+y_{2} }{2} )

So, for JK, points are J(1,4) and K(4,1). Replacing in the formula, we have

m_{JK} =(\frac{1+4}{2} ,\frac{4+1}{2} )\\m_{JK} =(\frac{5}{2} ,\frac{5}{2} )\\m_{JK} =(2.5 ,2.5)

For LK, points are L(0,-1) and K(4,1)

m_{LK} =(\frac{0+4}{2} ,\frac{-1+1}{2} )\\m_{LK} =(\frac{4}{2} ,\frac{0}{2} )\\m_{LK} =(2 ,0)

This means that the endpoint coordinates for the midsegment that is parallel to JL are (2.5, 2.5) and (2,0).

nirvana33 [79]4 years ago
3 0
(2.5, 2.5) and (2, 0)
But you knew that already
sorry
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The speed of wind and speed of plane in still air  are  23  and  135 km/h respectively.

<u>Step-by-step explanation:</u>

Let the speed of wind and speed of plane in still air  are  w  and  p km/h respectively.  

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A. Steven wrote an expression with 2 terms. The second term, which is the whole number 7, is subtracted from the first term. The
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Step-by-step explanation:

Part a)

Let

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2(2x+5)^{2}-7

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Let

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