The electron group arrangement of PH₃ is tetrahedral. The molecular shape is a Trigonal pyramid, and the bond angle is 93°.
<h3>What is the bond angle?</h3>
The angle between the atoms in a compound is known as the bond angle. The degree of the binding angle is specified. There is also the bond length. It is the separation between the two atoms' nuclei.
The bond angle between the atoms of phosphine is 93°. It has one lone pair. The central atom is covered with 4 atoms.
Thus, the electron-group arrangement of phosphine is tetrahedral. The molecular geometry or shape is a trigonal pyramid. The bond angle is 93°.
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Answer:
See Explanation
Explanation:
The equation of the reaction;
KHSO4(aq) + KOH(aq) -------> K2SO4(aq) + H2O(l)
Number of moles of KHSO4 = 49.6 g/136.169 g/mol = 0.36 moles
Since the reaction is in a mole ratio of 1:1, 0.36 moles of K2SO4 is produced.
Number of moles of KOH = 25.3 g/56.1056 g/mol = 0.45 moles
Since the reaction is 1:1, 0.45 moles of K2SO4 is produced
Hence K2SO4 is the limiting reactant.
Mass of K2SO4 formed = 0.36 moles of K2SO4 * 174.26 g/mol = 62.7 g
So;
1 mole of KHSO4 reacts with 1 mole of KOH
0.36 moles of KHSO4 reacts with 0.36 * 1/1 = 0.36 moles of KOH
Amount of excess KOH = 0.45 moles - 0.36 moles = 0.09 moles
Mass of excess KOH = 0.09 moles * 56.1056 g/mol = 5 g of excess KOH
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Answer: (D) 0.025 mol 
Explanation:
The given balanced equation is :
According to stoichiometry :
4 moles of ammonia 
reacts with = 5 moles of oxygen 
Thus 0.30 moles of ammonia reacts with = 
moles of oxygen
Now as given moles of oxygen are more than the required amount, oxygen is the excess reagent.
moles of oxygen left = 0.40 - 0.375 = 0.025
Thus 0.025 mol excess reagent remains.
