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alexgriva [62]
4 years ago
14

What is the maximum number of electrons in oxygen Adam can hold in its outer energy level

Chemistry
1 answer:
adell [148]4 years ago
8 0
Do you mean atom :).
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How many joules would be absorbed for the water in Problem 1
9966 [12]

Answer:

5000 cal X 4.184 J/cal =

Explanation:

20,920 jules

8 0
4 years ago
How many energy levels does sulfur have?<br> A. 2<br> B. 3<br> C. 4<br> D. 14
Karolina [17]
Its electronic confuguration is 2.8.6 so it occupies 3 shells.
7 0
4 years ago
An airplane began with an initial velocity of 120 m/s and ended with a final velocity of 180 m/s in 4 seconds. What was its acce
Semmy [17]

Answer:

B

Explanation:

180-120=60

60/4=15

6 0
3 years ago
Read 2 more answers
Some plant seeds are adapted to develop only at extremely high temperatures. For what environmental change are
Hoochie [10]

Answer:

Forest Fire

Explanation:

Forest fire is an ecological factor over which biological processes like seed dispersal and their germination is dependent upon. Some plants germinate under high temperature underground regions of the soil which is covered by the hot soil affected by the burning by the forest fire. Some of the coniferous trees like longpole pines have hard cone which exhibit the seeds. These cones exhibit the serotonin resins which are melted by the forests fire hence fire helps in dispersal of the seeds.  Other plants like Eucalyptus and Banksia are also dependent upon fire for seed dispersal.

4 0
3 years ago
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A 1.00 g sample of a hydrogen peroxide (H2O2) solution is placed in an Erlenmeyer flask and diluted with 20 mL of 1 M aqueous su
Minchanka [31]
Following reaction is involved in present system:

2KMnO4  +  5H2O2 +  3H2SO4 →  2MnSO4    +     K2SO4  + 5O2  +   8H2O

From the above balance reaction, it can be seen that 2 moles of KMnO4 is consumed for every 5 moles of H2O2.

 Now, percent by mass of hydrogen peroxide in the original solution can be estimated as follows:
percent by mass = \frac{\text{mass of H2O2(g)}}{\text(volume of H2SO4(ml))}X 100
∴percent by mass = \frac{\text{1}}{\text(25)}X 100
                             = 4 % 
5 0
3 years ago
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