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3 years ago

A crate feels a 277 n normal force as it sits on the ground. what is its mass?

Physics

2 answers:

Galina-37 [17]3 years ago

6 0

Answer:

28.3 kg

Explanation:

Assuming the ground is level, the normal force equals the weight.

N = mg

277 N = m × 9.8 m/s²

m = 28.3 kg

Umnica [9.8K]3 years ago

5 0

Answer:

28.3 kg

Explanation:

Assuming the ground is level, the normal force equals the weight.

N = mg

277 N = m × 9.8 m/s²

m = 28.3 kg

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A uniform, solid, 2000.0 kgkg sphere has a radius of 5.00 mm. Find the gravitational force this sphere exerts on a 2.10 kgkg poi

mars1129 [50]

Answer:

$0.0110284391534\ N$

$0.0653784219002\ N$

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

$m_1$ = Mass of sphere = 2000 kg

$m_2$ = Mass of other sphere = 2.1 kg

r = Distance between spheres

Force of gravity is given by

$F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 2000\times 2.1}{(5.04\times 10^{-3})^2}\\\Rightarrow F=0.0110284391534\ N$

The gravitational force is $0.0110284391534\ N$

$F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 2000\times 2.1}{(2.07\times 10^{-3})^2}\\\Rightarrow F=0.0653784219002\ N$

The gravitational force is $0.0653784219002\ N$

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2 years ago

In 2-3 complete sentences, explain why the needle on a compass always points in the direction of magnetic north.

Alex17521 [72]

The needle on a compass always points in the direction of magnetic north because of the magnetic poles of earth. the compass is essentially a magnet itself, so the southern pole of the compass is attracted to the northern pole of earth.

8 0

2 years ago

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Which groups of organisms became extinct during the Paleozoic Era

guapka [62]

Dinosaurs but I need the whole groups yo tell you ;)

4 0

2 years ago

A scaffold of mass 57 kg and length 6.5 m is supported in a horizontal position by a vertical cable at each end. A window washer

Mrac [35]

Explanation:

The given data is as follows.

$m_{1}$ = 57 kg, $m_{2}$ = 79 kg

$l_{1}$ = 6.5 m, $l_{2}$ = (6.5 - 1.9) m = 4.6 m

(a) The sum of torque ends about far end is as follows.

$m_{1}g \frac{l_{1}}{2} + m_{2}g \times l_{2} - T \times l_{1}$ = 0

$57 \times 9.81 \times \frac{6.5}{2} + 79 \times 9.81 \times (6.5 - 1.9) - T \times 6.5$ = 0

T = 828 N

Therefore, 828 N is the tension in the cable closer to the painter.

(b) Now, we will calculate the sum about close ends as follows.

$m_{1}g \frac{l_{1}}{2} + m_{2}g \times (1.9) - T \times l_{1}$

$57 \times 9.81 \times \frac{6.5}{2} + 79 \times 9.81 \times (1.9) - T \times 6.5$ = 0

T= 506 N

Therefore, 506 N is the tension in the cable further from the painter.

8 0

2 years ago

What is an athlete’s momentum if the athlete has a velocity of 7.5 m/s and has a mass of 70kg?

Bezzdna [24]

Answer:

525 kg.m/s

Explanation:

★ Momentum = Mass× Velocity

→ P = (7.5 × 70) kg.m/s

→ P = (75 × 7) kg.m/s

→ P = 525 kg.m/s

8 0

1 year ago