Question

Please help me with my physics! I do not understand and please provide work.

Answer 1

26) A) 400J as GPE = mgh
27) C) Both obj has same PE
28) B) It decreases as energy is not being provided.
29) C) (42 - 0)/7 = 6m/s2

Answer 2

26. Work = Force * distance or height

Force = mass * acceleration due to gravity (m*g)

So, Work = m * g * h

Work = 5 * 10 * 8 g is always = 10 m/s²

Work = 400J - (A)

27. Calc. the potential energy of both objects I and II

P.E = m * g * h

P.E of object I = 4 * 10 * 3 since g = 10 m/s²

= 120

P.E of object II = 6 * 10 * 2

=120

So, the potential energy of both objects are equal - III - (C)

29. Average acceleration = Increase in velocity/Elapsed time

The increase in velocity is 42 m/s

The elapsed time is 7 seconds

Average acceleration = 42/7 = 6 m/s² - (C)

28. It stays constant - (C)