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Morgarella [4.7K]
3 years ago
6

Please help me with my physics! I do not understand and please provide work.

Physics
2 answers:
Marrrta [24]3 years ago
5 0
26) A) 400J as GPE = mgh
27) C) Both obj has same PE
28) B) It decreases as energy is not being provided.
29) C) (42 - 0)/7 = 6m/s2
Dimas [21]3 years ago
4 0

26. Work = Force * distance or height

Force = mass * acceleration due to gravity (m*g)

So, Work = m * g * h

Work = 5 * 10 * 8 g is always = 10 m/s²

Work = 400J - (A)


27. Calc. the potential energy of both objects I and II

P.E = m * g * h

P.E of object I = 4 * 10 * 3 since g = 10 m/s²

= 120

P.E of object II = 6 * 10 * 2

=120

So, the potential energy of both objects are equal - III - (C)


29. Average acceleration = Increase in velocity/Elapsed time

The increase in velocity is 42 m/s

The elapsed time is 7 seconds

Average acceleration = 42/7 = 6 m/s² - (C)


28. It stays constant - (C)

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horrorfan [7]
Answer: 36 meters.


Equation to find distance:
Speed x time
8 0
3 years ago
At this radius, what is the magnitude of the net force that maintains circular motion exerted on the pilot by the seat belts, th
Ainat [17]

Answer:

Fc=5253 N

Explanation:

Answer:

Fc=5253 N

Explanation:

sequel to the question given, this question would have taken precedence:

"The 86.0 kg pilot does not want the centripetal acceleration to exceed 6.23 times free-fall acceleration. a) Find the minimum radius of the plane’s path. Answer in units of m."

so we derive centripetal acceleration first

ac (centripetal acceleration) = v^2/r

make r the subject of the equation

r= v^2/ac

 ac is 6.23*g which is 9.81

v is 101m/s

substituing the parameters into the equation, to get the radius

(101^2)/(6.23*9.81) = 167m

Now for part

( b) there are two forces namely, the centripetal and the weight of the pilot, but the seat is exerting the same force back due to newtons third law.

he net force that maintains circular motion exerted on the pilot by the seat belts, the friction against the seat, and so forth is the centripetal force.

Fc (Centripetal Force) = m*v^2/r  

So (86kg* 101^2)/(167) =

Fc=5253 N

4 0
3 years ago
If the 80 ohm resistor fails, will the 50 ohm and 100 ohm resistor continue to operate? Why or why not?
sleet_krkn [62]

Answer:

No, the 50 ohm and 100 ohm resistor will not continue to operate.

Explanation:

A closed circuit is the circuit in which there is no break between the negative and the positive end of the battery.

When in this, combinational circuit the 80 ohm resistor fail then there will not any continue supply of current in the circuit due to the breakage because the electron will flow from negative end of the battery to positive end if their is no breaking in the circuit.

Therefore the 50 ohm and 100 ohm circuit will not continue to operate because of the breaking of the circuit and current will not flow.

7 0
3 years ago
Why current remains same in series combination of resistors in all resistors and p.d. remains different?
IgorC [24]
Current at all points of a series circuit must be the same, because there's no place in the circuit where electrons are being manufactured, and no place where they're leaking out and falling on the floor. The nimber of electrons that leaves the loop is the same number that entered it. I'm not sure what is nmeant by "p.d. remains different" .
4 0
3 years ago
The diagram shows a spherical wave.
Vikki [24]

the answer to this question is y

9 0
3 years ago
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