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3 years ago

Please help me with my physics! I do not understand and please provide work.

Physics

2 answers:

Marrrta [24]3 years ago

5 0

26) A) 400J as GPE = mgh
27) C) Both obj has same PE
28) B) It decreases as energy is not being provided.
29) C) (42 - 0)/7 = 6m/s2

Dimas [21]3 years ago

4 0

26. Work = Force * distance or height

Force = mass * acceleration due to gravity (m*g)

So, Work = m * g * h

Work = 5 * 10 * 8 g is always = 10 m/s²

Work = 400J - (A)

27. Calc. the potential energy of both objects I and II

P.E = m * g * h

P.E of object I = 4 * 10 * 3 since g = 10 m/s²

= 120

P.E of object II = 6 * 10 * 2

=120

So, the potential energy of both objects are equal - III - (C)

29. Average acceleration = Increase in velocity/Elapsed time

The increase in velocity is 42 m/s

The elapsed time is 7 seconds

Average acceleration = 42/7 = 6 m/s² - (C)

28. It stays constant - (C)

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MakcuM [25]

Answer:

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Why is people to come together and combine their efforts?

Dovator [93]

Answer:

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3 years ago

Read 2 more answers

A rigid, insulated tank that is initially evacuated is connected though a valve to a supply line that carries steam at 1 MPa and

meriva

Answer:

Final Temperature of the steam tank = 456.4°C

Explanation:

Assuming it to be a uniform flow process, kinetic and potential energy to be zero, and work done and heat input to be zero also. We can conclude that,

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Using the Property tables and Charts - Steam tables,

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3 years ago

Spymaster Paul, flying a constant 215km/h horizontally in a low-flying helicopter, want to drop secret documents into his contac

aleksandrvk [35]

Answer:

$\theta = 49.56 degree$

Explanation:

Relative horizontal velocity of plane with respect to the car is given as

$v_r = v_p - v_c$

so we have

$v_p = 215 km/h$

$v_c = 155 km/h$

now we have

$v_r = 215 - 155$

$v_r = 60 km/h$

$v_r = 16.67 m/s$

Now time taken by the object to drop the vertical height is given as

$y = \frac{1}{2}gt^2$

$78 = \frac{1}{2}(9.81)t^2$

$t = 3.98 s$

so the distance of the car must be

$d = v_r\times t$

$d = 16.67 \times 3.98$

$d = 66.47 m$

Angle of the car with horizontal is given as

$tan\theta = \frac{y}{x}$

$tan\theta = \frac{78}{66.47}$

$\theta = tan^{-1}(1.17)$

$\theta = 49.56 degree$

5 0

3 years ago

The speed of light is about 3.00 × 105 km/s. It takes approximately 1.28 seconds for light reflected from the

Ulleksa [173]

Just to correct you - the speed of light is 3.0 x 10^5 km/sec and not 105 km/sec as given by you (maybe it was just a typing mistake from your end).

The average distance between earth and moon would be - 384,000 kms.

This is calculated by the formula -> Distance = Speed x Time.

8 0

3 years ago