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Morgarella [4.7K]
3 years ago
6

Please help me with my physics! I do not understand and please provide work.

Physics
2 answers:
Marrrta [24]3 years ago
5 0
26) A) 400J as GPE = mgh
27) C) Both obj has same PE
28) B) It decreases as energy is not being provided.
29) C) (42 - 0)/7 = 6m/s2
Dimas [21]3 years ago
4 0

26. Work = Force * distance or height

Force = mass * acceleration due to gravity (m*g)

So, Work = m * g * h

Work = 5 * 10 * 8 g is always = 10 m/s²

Work = 400J - (A)


27. Calc. the potential energy of both objects I and II

P.E = m * g * h

P.E of object I = 4 * 10 * 3 since g = 10 m/s²

= 120

P.E of object II = 6 * 10 * 2

=120

So, the potential energy of both objects are equal - III - (C)


29. Average acceleration = Increase in velocity/Elapsed time

The increase in velocity is 42 m/s

The elapsed time is 7 seconds

Average acceleration = 42/7 = 6 m/s² - (C)


28. It stays constant - (C)

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Georgia [21]
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3 years ago
You have a spring-loaded air rifle. When it is loaded, the spring is compressed 0.3 m and has a spring constant of 150 N/m. In j
Feliz [49]

The potential energy of the spring is 6.75 J

The elastic potential energy stored in the spring is given by the equation:

E= \frac{1}{2} kx^2

where;

k is the spring constant

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In this problem, we have the spring as follows:

k = 150 N/m is the spring constant

x = 0.3 m is the compression

Substituting in the equation, we get

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Learn more about potential energy here:

brainly.com/question/10770261

#SPJ4

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