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Morgarella [4.7K]
3 years ago
6

Please help me with my physics! I do not understand and please provide work.

Physics
2 answers:
Marrrta [24]3 years ago
5 0
26) A) 400J as GPE = mgh
27) C) Both obj has same PE
28) B) It decreases as energy is not being provided.
29) C) (42 - 0)/7 = 6m/s2
Dimas [21]3 years ago
4 0

26. Work = Force * distance or height

Force = mass * acceleration due to gravity (m*g)

So, Work = m * g * h

Work = 5 * 10 * 8 g is always = 10 m/s²

Work = 400J - (A)


27. Calc. the potential energy of both objects I and II

P.E = m * g * h

P.E of object I = 4 * 10 * 3 since g = 10 m/s²

= 120

P.E of object II = 6 * 10 * 2

=120

So, the potential energy of both objects are equal - III - (C)


29. Average acceleration = Increase in velocity/Elapsed time

The increase in velocity is 42 m/s

The elapsed time is 7 seconds

Average acceleration = 42/7 = 6 m/s² - (C)


28. It stays constant - (C)

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Aloiza [94]

Answer:

Water temperatures are slow to heat up, It takes 4 times the energy to heat up water than to heat air. Water also "feels" colder because water is a more efficent medium than air to cool our body down.

Re word it tho

Hope this helps!!

3 0
3 years ago
What is the velocity of an object that has a momentum of 4,000 kg-m/s and a mass of 115 kg? Round to the nearest hundredth.
julia-pushkina [17]
<h2>Answer: 34.78 m/s</h2>

Explanation:

The momentum p is given by the following equation:

p=m.V   (1)

Where:

m is the mass of the object

V is the velocity of the object

Finding the velocity from (1):

V=\frac{p}{m}   (2)

V=\frac{4000kg.m/s}{115kg}  

<u>Finally:</u>

V=34.78m/s >>>This is the velocity of the object

4 0
3 years ago
Read 2 more answers
Most exceptions to the trend of decreasing radius moving to the right within a period occur in the __________.
Gelneren [198K]

Answer:

Most exceptions to the trend of decreasing radius moving to the right within a period occur in the d-block.

Explanation:

  • In a period as we advance from left to right, the number of valence electrons in the same shell increases due to which the effective nuclear charge increases and thus the atomic size decreases.
  • In d-block atomic radius initially decreases then remains constant and increases towards the end.
  • As one moves from Sc (scandium) to Zn (zinc), the effective nuclear charge increases by a factor of 1, this is because:
  1. The number of electrons are low in the inner shell.
  2. The shielding power of d-orbital is low.
  3. Inter electronic repulsions will be operating at a value less than the nuclear charge, which will result in decrease in atomic radii.
  • As the number of electrons in the inner orbital increases the outer electrons repel one another which enables them to push away.
  • Although d-orbital has less shielding power, the number of electrons present in it are high. Hence, the electron-electron repulsive force becomes dominant, this results in an increase in the atomic radii.

Therefore, most exceptions to the trend of decreasing radius moving to the right within a period occur in the d-block.

Learn more about the periodic table here:

<u>brainly.com/question/9238898</u>

#SPJ4

8 0
2 years ago
The type of tectonic plate boundary that occurs when two plates are colliding into each other is known as a
ruslelena [56]
The answer is convergent boundary 
6 0
3 years ago
Read 2 more answers
A 2.4-kg cart is rolling along a frictionless, horizontal track towards a 1.7-kg cart that is held initially at rest. The carts
inessss [21]

Answer:

Explanation:

Mass of first cart M1=2.4kg

Velocity of first cart U1=4.1m/s

Mass of second cart M2=1.7kg

Second cart is initially at rest U2=0

After an instant, the velocity of the second cart is U2=-2.8m/s

Now after collision the two cart move together with the same velocity I.e inelastic collision

Using conservation of momentum

Momentum before collision, = momentum after collision

M1U1 + M2U2 = (M1+M2)V

2.4×4.1 + 1.7× -2.8 =(2.4+1.7)V

9.84 - 4.76 = 4.1V

5.08=4.1V

V=5.08/4.1

V=1.24m/s

The momentum of the two cart at that instant is

M1U1+M2U2

2.4×4.1 + 1.7× -2.8

9.84 - 4.76

5.08kgm/s

So the momentum at the instant the velocity is 4.1m/s for cart 1 and -2.8m/s for cart 2 is 5.08kgm/s

3 0
3 years ago
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