As per the given Figure attached here we know that both charges q1 and q2 will apply same force on charge q3 and hence the resultant force due to both charges will be along Y axis vertically upwards

So here we know that

$F = \frac{kq_1q_3}{d_{13}^2}$

now from the above equation

$F = \frac{(9\times 10^9)(2\times 10^{-6})(4 \times 10^{-6})}{0.5^2}$

$F = 0.288 N$

so both of the charges will apply 0.288 N force on q3 charge along the line joining them

now the net force due to vector sum is given by

$F_{net} = 2Fcos\theta$

here we know that angle is

$\theta = 37 degree$

now we have

$F_{net} = 2\times 0.288 cos37$

$F_{net} = 0.46 N$

so net force on q3 is 0.46 N vertically upwards along +Y axis

6 0

3 years ago

What does a Lewis structure diagram represent?

densk [106]

Answer:

correct me if i'm wrong nut i thinks its a The atomic symbol of an element surrounded by valence electrons

Explanation:

5 0

2 years ago

Read 2 more answers

Hanna tosses a ball straight up with enough speed to rermain in the air for several seconds

Ipatiy [6.2K]

What a relief ! That gives her time to step out of the way, before the ball
comes crashing down in the same place where she was standing.

7 0

3 years ago