3 years ago

An object rolls East at a steady speed of 12 m/s for 3 seconds. What distance did the object travel

Physics

1 answer:

horrorfan [7]3 years ago

8 0

Answer: 36 meters.

Equation to find distance:
Speed x time

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What is the current in a circuit that has voltage of 121.3 V and a total resistance of 56.3

Anuta_ua [19.1K]

Answer:

2.15 ampere

Explanation:

I = V/ R

= 121.3/56.3

= 2.15 A

3 0

3 years ago

Explain the difference between an electrically charged and a neutral object

Stella [2.4K]

An electrically charged element is called an "ion". A neutral element is an atom.

7 0

3 years ago

A tsunami covers a distance of 500km in 83.3 minutes. If the period of vibration of the molecules is 35.0 minutes, what is the w

marin [14]

Answer:

210079.798 m

Explanation:

pls give brainliest :)

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3 years ago

A person pushes two boxes with a horizontal force F of magnitude of 100 N.

Monica [59]

The magnitude of the action–reaction pair between the two boxes (A and B) will be "18.2 N".

According to the question,

Mass of box A,

$m_A = 9\ kg$

Mass of box B,

$m_B = 2 \ kg$

Horizontal force,

$F_{app} = 100 \ N$

From the Newton's law,

→ $F_{app} = (\frac{F_{app}}{m_A+m_B} )a$

or,

→ $a = \frac{F_{app}}{(m_A+m_B)}$

Bu substituting the values, we get

→ $= \frac{100}{9+2}$

→ $= \frac{100}{11}$

→ $9.10 \ m/s^2$

We can see that between the two boxes, the action-reaction pair exist.

then,

→ $F_{action-reaction} = m_b \ a$

→ $=2\times 9.10$

→ $= 18.2 \ N$ (magnitude)

Thus the above solution is appropriate.

Learn more about the magnitude here:

brainly.com/question/13545862

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3 years ago

A block with mass m =6.9 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.24 m.

Burka [1]

U need to set up n solve the general eqn for simple harmonic motion:
x" = -(k/m)x

solution is x(t) = (x0)*cos(wt) + (v0/w)*sin(wt)
where w=sqrt(k/m), x0 is x-position at t=0 and v0 is vel at t=0
u already calculated f in Q.2 and w = 2*pi*f
x0 is 0 as it starts at eqm
v0 is given at 5.1

so u have x(t)

vel is given by x'(t) = (x0)*(-w)*sin(wt) + (v0/w)*w*cos(wt)

substitute t=0.32, x0=0, v0=5.1 n w in the above, u can solve for v at t=0.32.

5 0

3 years ago