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lesya [120]
4 years ago
5

A real heat engine operates between temperatures Tc and Th. During a certain time, an amount Qc of heat is released to the cold

reservoir. During that time, what is the maximum amount of work Wmaxthat the engine might have performed?Express your answer in terms of Qc, Th, and Tc.
Physics
1 answer:
Ivanshal [37]4 years ago
4 0

Answer: Qc * (1 - Th/Tc)

Explanation:  

Maximum Work done = Qh * η

                                Wmax  = Qh * (1 - Tc/Th)

For reversible cycle of engine: Qc/Tc + Qh/Th = 0

                                                   Qh = -(Qc*Th)/Tc

Substituting Qh back into equation for work:

Wmax = -(Qc*Th)/Tc *  (1 - Tc/Th)

Wmax = -(Qc*Th)/Tc + Qc

Wmax = Qc * (1 - Th/Tc)

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Answer:

The rider's speed will be approximately 35 m/s

Explanation:

Initially the rider has kinetic and potential energy, and after going down the hill, some of the potencial energy turns into kinetic energy. So using the conservation of energy, we have that:

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