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3 years ago

What type of motion is shown with this graph? (5 points)

Physics

1 answer:

Vladimir [108]3 years ago

7 0

It should be Constant speed. The line goes straight & doesn’t change within the graph.

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A motor raises the car up the tower from point C to point A with a constant velocity. State Newton’s First Law of Motion and exp

GarryVolchara [31]

newton 1st law: w no external force, a body will stay at rest or in constant uniform motion.

a motor raises the car up the tower. cuz it moves w/ constant vel, there is no external force: the motor force is the same n in opposity direction as the gravity force on car.

8 0

3 years ago

Read 2 more answers

A rescue pilot drops a survival kit while her plane is flying at an ultitude of 2500m with a forward velocity of 95m. If the air

never [62]

Answer:

Approximately $2.1\; \rm km$ , assuming that $g = -9.8\; \rm m \cdot s^{-2}$ .

Explanation:

Let $t$ denote the time required for the package to reach the ground. Let $h(\text{initial})$ and $h(\text{final})$ denote the initial and final height of this package.

$\displaystyle h(\text{final}) = \frac{1}{2}\, g\, t^2 + h(\text{initial})$ .

For this package:

Initial height: $h(\text{initial}) = 2500\; \rm m$ .
Final height: $h(\text{final}) = 0\; \rm m$ (the package would be on the ground.)

Solve for $t$ , the time required for the package to reach the ground after being released.

$\displaystyle t^{2} = \frac{2\, (h(\text{final}) - h(\text{initial}))}{g}$ .

$\begin{aligned} t &= \sqrt{\frac{2\, (h(\text{final}) - h(\text{initial}))}{g} \\ &\approx \sqrt{\frac{2\times (0\; \rm m - 2500\; \rm m)}{(-9.8\; \rm m \cdot s^{-2})}} \approx 22.588\; \rm s\end{aligned}$ .

Assume that the air resistance on this package is negligible. The horizontal ("forward") velocity of this package would be constant (supposedly at $95\; \rm m \cdot s^{-1}$ .) From calculations above, the package would travel forward at that speed for about $22.588\; \rm s$ . That corresponds to approximately: $95\; \rm m \cdot s^{-1} \times 22.588\; \rm s \approx 2.1 \times 10^{3}\; \rm m = 2.1\; \rm km$ .

Hence, the package would land approximately $2.1\; \rm km$ in front of where the plane released the package.

5 0

3 years ago

The weakest gravitational force caused by the Moon is called the __________, which is found at the point on Earth farthest from

skad [1K]

This is called Nadir.

4 0

2 years ago

4800 g to kg? With the work pls

Zigmanuir [339]

Answer:

[See Below]

Explanation:

✦ Formula = $Mass / 1000$

✧ $4800 / 1000 = 4.8$

So $4800$ grams is equal to $4.8$ kilograms.

~<em>Hope this helps Mate. If you need anything feel free to message me. </em>

3 0

4 years ago

If a honeybee is flying 7.0 m/s, what is the kinetic energy (Joules) if its mass is 0.1 g?

svetlana [45]

Answer:

KINETIC ENERGY=K.E=0.00245 Joules ≈ 0.003 Joules

Explanation:

mass=m=0.1g=0.0001kg

velocity=v=7.0m/s

kinetic energy=K.E.=?

as we know that

$kinetic energy=\frac{1}{2}mv^2\\ putting values\\kinetic energy=\frac{1}{2}(0.0001kg)(7.0m/s)^2\\ kinetic energy=\frac{1}{2} 0.0049joules\\kinetic energy= 0.00245Newton meter or joules$

hope it will help ^_^

5 0

3 years ago