Explanation:
Internal energy = heat + work
U = Q + W
Since there's no change in volume (rigid walls), W = 0.
U = Q
U = n Cᵥ ΔT
U = (4.0 mol) (2.5 × 8.314 J/mol/K) (354 C − 17 C)
U = 28,000 J
<span>The person is dragging
with a force of 58 lbs at an angle of 27 degrees relating to the ground. We
want to use cosine function to look for the horizontal force component. And
then we can compute for W = (Horizontal Force) x (Distance). We want the
horizontal force component since that is the component that is parallel to the
direction the cart is moving. </span><span>
(cos 27 degrees)(58 lbs) = 51.69 lbs (This is the horizontal
force component.)
W = (51.69 lbs) x (70 ft) = 3618.3 ft*lbs</span>
Answer:
This is because, the flywheel has a very large moment of Inertia and hence sudden piston torques have negligible effect on the flywheel, but every piston combined has a significant torque. This smoothens out the vibrations.
Explanation:
