Question

A compressor delivers 130 scfm of air through a 1-in schedule 40 pipe at a receiver pressure of 105 psig. Find the pressure loss for a 170-ft length of pipe

Answer 1

Answer:

The pressure loss in the pipe is 7.792 psig

Explanation:

Given;

flow rate Q = 130 scfm

length of pipeline =170ft

atmospheric pressure = 14.7 psia

pressure in pipe = 105 psig, to psia = 105 + 14.7 = 119.7 psia

Compression ratio (CR) = pressure in pipe/atmospheric pressure

Compression ratio (CR) = 119.7/14.7 = 8.143

Pressure loss in the pipe can be calculated as follows:

$P_L=\frac{0.1025LQ^2}{3600*CR*d^{5.31}}$

from schedule table, 1-in schedule 40 pipe has a diameter d.

$d^{5.31} = 1.2892$

Substituting these values, pressure loss in the pipe becomes

$P_L=\frac{0.1025LQ^2}{3600*CR*d^{5.31}} = \frac{0.1025*170*(130)^2}{3600*8.143*1.2892} = 7.792 psig = 22.492 psi$

Therefore, the pressure loss in the pipe is 7.792 psig