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3 years ago

In order for work to be done, what three things are necessary?

Physics

2 answers:

andrey2020 [161]3 years ago

6 0

The three things that are necessary are power, a force, and movement in the opposite direction of the applied force.

meriva3 years ago

4 0

Answer:

unbalanced force, motion, and movement in the same direction of the applied force

Explanation:

Work Done is actually the product of force and distance. If force is applied without covering a distance in the direction of the force then work is zero

Force, we know, is that we tend to change a body's state of rest or uniform motion on a straight line. Force is also the pull or push on an object

so In order for work to be done, what three things are necessary?

unbalanced force, motion, and movement in the same direction of the applied force

if there is a balanced force applied on the body , motion won't occur .In Fact the body will be at equilibrium which means zero work.

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What is the frequency of a wave that has a wavelength of 20 cm and a speed of 10 m/s

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You would probably have a low frequency due to how much the wavelength is spread out.

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3 years ago

Calculate the de Broglie wavelength of: a) A person running across the room (assume 180 kg at 1 m/s) b) A 5.0 MeV proton

solmaris [256]

Answer:

$\lambda = 3.68 *10^{-36} \ m$

$\lambda_p = 1.28*10^{-14} \ m$

Explanation:

From the question we are told that

The mass of the person is $m = 180 \ kg$

The speed of the person is $v = 1 \ m/s$

The energy of the proton is $E_ p = 5 MeV = 5 *10^{6} eV = 5.0 *10^6 * 1.60 *10^{-19} = 8.0 *10^{-13} \ J$

Generally the de Broglie wavelength is mathematically represented as

$\lambda = \frac{h}{m * v }$

Here h is the Planck constant with the value

$h = 6.62607015 * 10^{-34} J \cdot s$

$\lambda = \frac{6.62607015 * 10^{-34}}{ 180 * 1 }$

=> $\lambda = 3.68 *10^{-36} \ m$

Generally the energy of the proton is mathematically represented as

$E_p = \frac{1}{2} * m_p * v^2_p$

Here $m_p$ is the mass of proton with value $m_p = 1.67 *10^{-27} \ kg$

=> $8.0*10^{-13} = \frac{1}{2} * 1.67 *10^{-27} * v^2$

=> $v _p= \sqrt{\frac{8.0 *10^{-13}}{ 0.5 * 1.67 *10^{-27}} }$

=> $v = 3.09529 *10^{7} \ m/s$

$\lambda_p = \frac{h}{m_p * v_p }$

so $\lambda_p = \frac{6.62607015 * 10^{-34}}{1.67 *10^{-27} * 3.09529 *10^{7} }$

=> $\lambda_p = 1.28*10^{-14} \ m$

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3 years ago

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Slav-nsk [51]

Answer:

945 j

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3 years ago

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pashok25 [27]

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3 years ago

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PolarNik [594]

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Learn more about z-score here:

brainly.com/question/21262765

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2 years ago