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3 years ago

Melanie made the following diagram shown to represent some phases of the moon as seen from Earth.

Physics

1 answer:

timofeeve [1]3 years ago

6 0

Answer:

D. The position of the first quarter moon and third quarter moon have been interchanged.

Explanation:

Phases of moon are the shapes of illuminated portion of the moon that is visible from the earth.

New moon occurs when the moon comes between the earth and the sun. The lit portion faces away from the earth.

After new moon, waxing crescent phase occurs followed by first quarter. In the first quarter, half moon is visible.

Waxing gibbous occurs which is when more than half and less than full face of the moon is visible. This is followed by full moon when earth comes between moon and the sun.

The waning gibbous phase is visible for next few days till the third quarter phase. Then waning crescent phase and finally new moon again.

In the given diagram made by Melanie, the position of first quarter and third quarter are wrong and must be interchanged.

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Select all that apply. There MIGHT be more than one.

Stolb23 [73]

I believe the answer to your question is “Lithosphere plate boundaries”

The planet Earth is covered by a layer formed by land and rocks called the earth's crust or lithosphere. This crust is not smooth and uniform, but rather irregular and composed of tectonic plates, also called lithosphere plates. These plates are not fixed as they are under the magma (high temperature molten rock).

Hope this helps!:)

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2 years ago

How many times has the Sun orbited around the Milky Way since the Sun first formed, if the Sun makes one orbit every 231 million

natta225 [31]

Answer:

It would depend on the amount of years.

Explanation:

I don’t think this is very helpful-

Have a great day!

Anygays-

5 0

2 years ago

Holden is trying to determine the velocity of his race car. He went 20 meters east, turned around, and went 40 meters west. His

Ludmilka [50]

Answer:

12 m/s west

Explanation:

4 0

3 years ago

Read 2 more answers

Cuanto cambia la entropía de 0.50 kg de vapor de mercurio [Lv: 2.7 x 10⁵ j/kg ] al calentarse en su punto de ebullición de 357°

lord [1]

Answer:

La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.

Explanation:

Por definición de entropía ( $S$ ), medida en joules por Kelvin, tenemos la siguiente expresión:

$dS = \frac{\delta Q}{T}$ (1)

Donde:

$Q$ - Ganancia de calor, en joules.

$T$ - Temperatura del sistema, en Kelvin.

Ampliamos (1) por la definición de calor latente:

$dS = \frac{L_{v}}{T}\cdot dm$ (1b)

Donde:

$m$ - Masa del sistema, en kilogramos.

$L_{v}$ - Calor latente de vaporización, en joules

Puesto que no existe cambio en la temperatura durante el proceso de vaporización, transformamos la expresión diferencial en expresión de diferencia, es decir:

$\Delta S = \frac{\Delta m \cdot L_{v}}{T}$

Como vemos, el cambio de la entropía asociada al cambio de fase del mercurio es directamente proporcional a la masa del sistema. Si tenemos que $m = 0.50\,kg$ , $L_{v} = 2.7\times 10^{5}\,\frac{J}{kg}$ and $T = 630.15\,K$ , entonces el cambio de entropía es:

$\Delta S = \frac{(0.50\,kg)\cdot \left(2.7\times 10^{5}\,\frac{J}{kg} \right)}{630.15\,K}$

$\Delta S = 214.235 \,\frac{J}{K}$

La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.

3 0

3 years ago

When a net force of 17.0 newtons is applied to a dictionary placed on a frictionless table, it accelerates by 3.75 meters/second

4vir4ik [10]

Force = (mass) x (acceleration) (Newton's second law of motion)

Divide both sides of the equation by 'acceleration', and you have

Mass = (force) / (acceleration)

Mass = 17 newtons / 3.75 meters per second-sqrd = 4.533 kilograms (rounded)

8 0

2 years ago