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Brums [2.3K]
3 years ago
15

Melanie made the following diagram shown to represent some phases of the moon as seen from Earth.

Physics
1 answer:
timofeeve [1]3 years ago
6 0

Answer:

D. The position of the first quarter moon and third quarter moon have been interchanged.    

Explanation:

Phases of moon are the shapes of illuminated portion of the moon that is visible from the earth.

New moon occurs when the moon comes between the earth and the sun. The lit portion faces away from the earth.

After new moon, waxing crescent phase occurs followed by first quarter. In the first quarter, half moon is visible.

Waxing gibbous occurs which is when more than half and less than full face of the moon is visible. This is followed by full moon when earth comes between moon and the sun.

The waning gibbous phase is visible for next few days till the third quarter phase. Then waning crescent phase and finally new moon again.

In the given diagram made by Melanie, the position of first quarter and third quarter are wrong and must be interchanged.

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In the diagnostic radiology energy range (which includes mammography) from 23 to 150 kVp, which of the following tissues possess
Semmy [17]

Answer:

Bone

Explanation:

Diagnostic radiology include the use of non-invasive imaging scans to diagnose a patient.

The voltages used in diagnostic tubes range from roughly 20 kV to 150 kV and thus the highest energies of the X-ray photons range from roughly 20 keV to 150 keV.

The tests and equipment used sometimes involves low doses of radiation to create highly detailed images of an area.

4 0
3 years ago
If a coin has a mass of 29.34g and drops from a height of 14.7 meters, what is its loss in gravitational potential energy? Show
Serga [27]
U= mgh
U=((29.34/1000)kg)(9.81 \frac{m}{s^{2} } )(14.7m)=4.321J

do not forget to change grams to kilograms and if it were in centimeters convert them to meters.
7 0
3 years ago
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7nadin3 [17]

Answer:

I'm pretty sure it's 37.5 joules of energy

Explanation:

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8 0
3 years ago
Help me calculate the kinetic energy (just the middle column) ASAP! SHOW WORK! ON PAPER
lukranit [14]

Answer:

Explanation:

I can tell you what the answers for the middle column are, but if you don't know how to solve total energy problems, they won't make any sense to you at all.

First row, KE = 0

Second row, KE = 220500 J

Third row, KE = 183750 J

Fourth row, KE = 205800 J

That's also not paying any attention to significant digits because your velocity only had 1 and that's not enough to do the problem justice. I left all the digits in the answer. Round how your teacher tells you to.

3 0
3 years ago
During 57 seconds of use, 330 C of charge flow through a microwave oven. Compute the size of the electric current.
swat32

Answer:

5.78amps

Explanation:

Given data

Time t= 57 seconds

Charge Q= 330C

Current I= ??

The expression for the electric current is given as

Q= It

Substituting we have

330= I*57

I= 330/57

I=5.78 amps

Hence the current is 5.78amps

3 0
3 years ago
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