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VMariaS [17]
3 years ago
8

According to bohr's model of the atom in which orbitals do electrons have the least energy

Chemistry
1 answer:
sasho [114]3 years ago
7 0
According to Bohr's model of the atom, the higher the orbital in which the electrons are found, the higher their energy or excitation state. Therefore, the electrons with the least amount of energy are those at the lowest orbitals, which are closer to the nucleus. 
These orbitals are characterized by 4 quantum numbers, namely the principal quantum number (n), orbital angular momentum quantum number (l), the magnetic quantum number (ml), and the electron spin quantum number (ms). The principal quantum number reflects the distance of the electrons from the nucleus with n=1 as the orbital closest to the nucleus. Thus, according to Bohr's model, electrons in the orbital with n=1 have the lowest energy. 
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How many grams of H2 can be formed from 54.6 grams of NH3 in the following reaction? 2NH3 (g) --> 3H2 (g) + N2 (g)
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9.64g

Explanation:

The balanced equation for the reaction is given below:

2NH3 (g) —> 3H2 (g) + N2 (g)

Next, we need to calculate the mass NH3 that decomposed and the mass of H2 produced from the balanced equation. This is illustrated below:

Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 that decomposed from the balanced equation = 2 x 17 = 34g

Molar Mass of H2 = 2x1 = 2g/mol

Mass of H2 produced from the balanced equation = 3 x 2 = 6g.

Now, we can obtain the mass of H2 formed from 54.6g of NH3 as follow:

From the balanced equation above,

34g of NH3 decomposed to produce 6g of H2.

Therefore, 54.6g of NH3 will decompose to produce = (54.6x6)/34 = 9.64g of H2

Therefore, 9.64g of H2 can be obtained from 54.6g of NH3.

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