Answer:
518 mL
Explanation:
We can solve this using Boyle's Law Formula
P1V1 = P2V2
where p1 = initial pressure, p2 = final pressure, v1 = initial volume and v2 = final volume
here , the initial pressure is 1 atm and the initial volume is 725mL
we are given the final pressure 1.4 and we need to find the final volume
so we have p1v1 = p2v2
==> plug in p1 = 1 , v1 = 725 mL and p2 = 1.4
(1)(725) = (1.4)v2
==> multiply 1 and 725
725 = (1.4)(v2)
==> divide both sides by 1.4
v2 = 518
N2 would have a volume of 518mL at 1.4atm
Answer:
1.41 moles H2O2(with sig figs)
Explanation:
okay so what is the molar mass of H2O2= (1.008 g/mol)2+(16.00g/mol)2= (2.016+ 32.00) g/ mol
= 34. 02 g/mol
48.0g H2O2* 1 mol H2O2/ 34.02 g H2O2= 1.41 mol H2O2
The hydrogens and oxygen of a water molecule are held together by covalent bond
Answer: A. Cilla Is Correct.