Answer:
More than 2,000 Years Ago, the Greek philosopher Aristotle suggested a model of the solar system. Aristotle's model was geocentric, or Earth-centered. In the model. the sun, stars, planets revolved around the Earth. In 150 AD an astrologer named Ptolemy began to support Aristotle's geocentric model.
In 1543 AD, an astronomer named Copernicus proposed a heliocentric model of the solar system. In this model, the planets revolve around the sun. Due to the invention of the telescope, the solar system could be explored in more detail. Galileo used the telescope to support Copernicus's theory of the sun being the center of the universe.
In the late 1500's, Kepler developed a law that explained planetary motion. Kepler's law is so accurate we still use them today.
Explanation:
Can you show me the rest of the question? I can not see it. Also, I know this is multiple choice fill in the blanks so I might be wrong. I hope that this helped though. This took a lot of research. The websites I used are commented down below. |
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2-Methyl-4-oxo-pentanoic acid is unlikely to produce 2-Methyl-3-butanone upon strong heating.
Upon heating, the β ketoacid becomes unstable and decarboxylates, leading to the formation of the methyl ketone.
A carboxylic acid is an organic acid that contains a carboxyl group (C(=O)OH) attached to an R-group. The general formula of a carboxylic acid is R−COOH or R−CO2H, with R referring to the alkyl, alkenyl, aryl, or other group.
Carboxylic acids occur widely. Important examples include the amino acids and fatty acids. Deprotonation of a carboxylic acid gives a carboxylate anion.
Full question :
Q. Which reactant is unlikely to produce the indicated product upon strong heating?
- A) 2,2-Dimethylpropanedioic acid 2-methylpropanoic acid
- B) 2-Ethylpropanedioic acid Butanoic acid
- C) 2-Methyl-3-oxo-pentanoic acid 3-Pentanone
- D) 2-Methyl-4-oxo-pentanoic acid 2-Methyl-3-butanone
- E) 4-Methyl-3-oxo-heptanoic acid 3-Methyl-2-hexanone
Hence, option (D) is correct.
Learn more about carboxylic acid here : brainly.com/question/26855500
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Answer:
d. K<1 E∘cell is negative
Explanation:
Since E⁰ = negative , ΔG = -nFE⁰ = -nF -ve = +ve.
Also, ΔG = -RTlnK
K = exp(-RTΔG)
Since ΔG = +ve, -RTΔG = -ve
K = 1/exp(RTΔG) < 1.
So our answer is E⁰ cell is negative and K < 1