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Ksivusya [100]
3 years ago
12

The Gulf Stream is a current that carries water north along the eastern coast of the United States. Which of the following descr

ibes the flow of water in the Gulf Stream?
A.
Cool water follows a path to join other cool water.
B.
Warm water follows a path to join other warm water.
C.
Warm water is carried to cooler parts of the ocean.
D.
Cool water is carried to warmer parts of the ocean.
Chemistry
1 answer:
ozzi3 years ago
8 0

The correct answer is - C. Warm water is carried to cooler parts of the ocean.

The Gulf Stream is warm ocean current. It is an ocean current that originates from the Caribbean region, where it is constantly warm throughout the year. Because of that, the water is warm as well, and since the warm water is less dense, it moves on the surface. The movement is toward the higher latitudes, where this current, as a surface movement of the water, is bringing warmer water to the cooler areas, such as the eastern coast of the United States. Not only that warm water is brought to these areas, but the Gulf Stream also brings in warm and moist air masses with it, making the climate much more mild, and increasing the amount of precipitation.

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during the processes of erosion and deposition sediments that are the ____ in size will be carried the greatest distances before
Harlamova29_29 [7]
<span>Smallest sediments will go the farthest. Usually sand or silt size grains.</span>
8 0
3 years ago
Which of the following defines the wavelength of a wave? A. the distance between peaks of a wave B. the speed that a wave is pas
Maru [420]

Answer:

D.the wavelength of a wave is the distance between two successive peaks or two successive troughs or a peak and trough

5 0
4 years ago
Read 2 more answers
Go'=30.5 kJ/mol
makvit [3.9K]

Answer:

a) Keq = 4.5x10^-6

b) [oxaloacetate] = 9x10^-9 M

c) 23 oxaloacetate molecules

Explanation:

a) In the standard state we have to:

ΔGo = -R*T*ln(Keq) (eq.1)

ΔGo = 30.5 kJ/moles = 30500 J/moles

R = 8.314 J*K^-1*moles^-1

Clearing Keq:

Keq = e^(ΔGo/-R*T) = e^(30500/(-8.314*298)) = 4.5x10^-6

b) Keq = ([oxaloacetate]*[NADH])/([L-malate]*[NAD+])

4.5x10^-6 = ([oxaloacetate]/(0.20*10)

Clearing [oxaloacetate]:

[oxaloacetate] = 9x10^-9 M

c) the radius of the mitochondria is equal to:

r = 10^-5 dm

The volume of the mitochondria is:

V = (4/3)*pi*r^3 = (4/3)*pi*(10^-15)^3 = 4.18x10^-42 L

1 L of mitochondria contains 9x10^-9 M of oxaloacetate

Thus, 4.18x10^-42 L of mitochondria contains:

molecules of oxaloacetate = 4.18x10^-42 * 9x10^-9 * 6.023x10^23 = 2.27x10^-26 = 23 oxaloacetate molecules

3 0
4 years ago
Two chemicals A and B are combined to form a chemical C. The rate, or velocity, of the reaction is proportional to the product o
stiv31 [10]

Answer:

Follows are the solution:

Explanation:

A + B = C

Its response decreases over time as well as consumption of a reactants.  

r = -kAB

during response A convert into 2x while B convert into x to form 3x of C

let's  y = C

y = 3x

Still not converted sum of reaction  

for A: 100 - 2x

for B: 50 - x

Shift of x over time  

\frac{dx}{dt} = \frac{-k(100 - 2x)}{(50 - x)}

Integration of x as regards t  

\frac{1}{[(100 - 2x)(50 - x)]} dx = -k dt\\\\\frac{1}{2[(50 - x)(50 - x)]} dx = -k dt\\\\\ integral\  \frac{1}{2[(50 - x)^2]} dx =\ integral [-k ] \ dt\\\\\frac{-1}{[100-2x]} = -kt + D \\\\

D is the constant of integration

initial conditions: t = 0, x = 0

\frac{-1}{[100-2x]} = -kt + D   \\\\\frac{ -1}{[100]} = 0 + D\\\\D= \frac{-1}{100}\\\\

hence we get:

\frac{-1}{[100-2x]}= -kt -\frac{1}{100}\\\\or \\\\ \frac{1}{(100-2x)} = kt + \frac{1}{100}

after t = 7 minutes , C = 10 \ g = 3x

3x = 10\\\\x = \frac{10}{3}

Insert the above value x into \frac{1}{(100-2x)} equation = kt + \frac{1}{100} to get k.  

\to  \frac{1}{(100-2\times \frac{10}{3})}  = k \times (7) + \frac{1}{100} \\\\ \to  \frac{1}{(100- 2 \times 3.33)} =   \frac{700k + 1}{100} \\\\ \to  \frac{1}{(100-6.66)} = \frac{700k + 1}{100}\\\\ \to \frac{1}{93.34} = \frac{700k + 1}{100} \\\\

\to 100 =  93.34(700k + 1) \\\\ \to 100 =  65,338k + 700 \\\\ \to   65,338k =  -600 \\\\ \to  k =  \frac{-600}{ 65,338} \\\\ \to k= - 0.0091

therefore plugging in the equation the above value of k  

\to \frac{1}{(100-2x)} = kt +\frac{1}{100} \\\\\to \frac{1}{(100-2x)} = -0.0091t + \frac{1}{100}\\\\\to \frac{1}{(100-2x)} =  \frac{1 -0.91t}{100}\\\\\to \frac{1}{2(50-x)} =  \frac{1 -0.91t}{100}\\\\\to \frac{1}{(50-x)} =  \frac{1 -0.91t}{50}\\\\\to 50= (1-0.91t)(50-x)\\\\\to 50 = 50-45.5t-x-0.91tx\\\\\to x+0.91xt= -45.5t\\\\\to x(1+0.91t)= -45.5t\\\\\to x=\frac{-45.5t}{1+0.91t}

Let y = C

, calculate C:

y = 3x

y =3 \times \frac{-45.5t}{1+0.91t}

amount of C formed in 28 mins

x = \frac{-45.5t}{1+0.91t} , plug t = 28

\to x = \frac{-1274}{1+25.48} \\\\\to x = \frac{-1274}{26.48} \\\\\to x= -48.26

therefore amount of C formed in 28 minutes is = 3x = 144.78 grams

C: y =3 \times \frac{-45.5t}{1+0.91t}

y= 136.5 =137

7 0
3 years ago
A 0.420 M Ca(OH)2 solution was prepared by dissolving 64.0 grams of Ca(OH)2 in enough water. What is the total volume of the sol
nikitadnepr [17]

The volume of the solution is given below which can be calculated using the molarity formula as 2.18 litres.

<h3>Define the molarity of a solution.</h3>

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.

Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}

Given data:

M= 0.420M

mass = 64.0 grams

Molar Mass= 74g/mol

To find:

The volume of solution=?

The calculation for a number of moles:

n= \frac{m}{M}

n= \frac{64}{70}

n= 0.91 moles

Molarity=  \frac{n}{V}

V= \frac{0.91}{0.420}

V= 2.1768 litres

Thus, the volume of the solution is 2.18 litres.

Find more information about Molarity here:

brainly.com/question/26873446

#SPJ1

6 0
2 years ago
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