<span>Smallest sediments will go the farthest. Usually sand or silt size grains.</span>
Answer:
D.the wavelength of a wave is the distance between two successive peaks or two successive troughs or a peak and trough
Answer:
a) Keq = 4.5x10^-6
b) [oxaloacetate] = 9x10^-9 M
c) 23 oxaloacetate molecules
Explanation:
a) In the standard state we have to:
ΔGo = -R*T*ln(Keq) (eq.1)
ΔGo = 30.5 kJ/moles = 30500 J/moles
R = 8.314 J*K^-1*moles^-1
Clearing Keq:
Keq = e^(ΔGo/-R*T) = e^(30500/(-8.314*298)) = 4.5x10^-6
b) Keq = ([oxaloacetate]*[NADH])/([L-malate]*[NAD+])
4.5x10^-6 = ([oxaloacetate]/(0.20*10)
Clearing [oxaloacetate]:
[oxaloacetate] = 9x10^-9 M
c) the radius of the mitochondria is equal to:
r = 10^-5 dm
The volume of the mitochondria is:
V = (4/3)*pi*r^3 = (4/3)*pi*(10^-15)^3 = 4.18x10^-42 L
1 L of mitochondria contains 9x10^-9 M of oxaloacetate
Thus, 4.18x10^-42 L of mitochondria contains:
molecules of oxaloacetate = 4.18x10^-42 * 9x10^-9 * 6.023x10^23 = 2.27x10^-26 = 23 oxaloacetate molecules
Answer:
Follows are the solution:
Explanation:
A + B = C
Its response decreases over time as well as consumption of a reactants.
r = -kAB
during response A convert into 2x while B convert into x to form 3x of C
let's y = C
y = 3x
Still not converted sum of reaction
for A: 100 - 2x
for B: 50 - x
Shift of x over time

Integration of x as regards t
![\frac{1}{[(100 - 2x)(50 - x)]} dx = -k dt\\\\\frac{1}{2[(50 - x)(50 - x)]} dx = -k dt\\\\\ integral\ \frac{1}{2[(50 - x)^2]} dx =\ integral [-k ] \ dt\\\\\frac{-1}{[100-2x]} = -kt + D \\\\](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5B%28100%20-%202x%29%2850%20-%20x%29%5D%7D%20dx%20%3D%20-k%20dt%5C%5C%5C%5C%5Cfrac%7B1%7D%7B2%5B%2850%20-%20x%29%2850%20-%20x%29%5D%7D%20dx%20%3D%20-k%20dt%5C%5C%5C%5C%5C%20integral%5C%20%20%5Cfrac%7B1%7D%7B2%5B%2850%20-%20x%29%5E2%5D%7D%20dx%20%3D%5C%20integral%20%5B-k%20%5D%20%5C%20dt%5C%5C%5C%5C%5Cfrac%7B-1%7D%7B%5B100-2x%5D%7D%20%3D%20-kt%20%2B%20D%20%5C%5C%5C%5C)
D is the constant of integration
initial conditions: t = 0, x = 0
![\frac{-1}{[100-2x]} = -kt + D \\\\\frac{ -1}{[100]} = 0 + D\\\\D= \frac{-1}{100}\\\\](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B%5B100-2x%5D%7D%20%3D%20-kt%20%2B%20D%20%20%20%5C%5C%5C%5C%5Cfrac%7B%20-1%7D%7B%5B100%5D%7D%20%3D%200%20%2B%20D%5C%5C%5C%5CD%3D%20%5Cfrac%7B-1%7D%7B100%7D%5C%5C%5C%5C)
hence we get:
![\frac{-1}{[100-2x]}= -kt -\frac{1}{100}\\\\or \\\\ \frac{1}{(100-2x)} = kt + \frac{1}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B%5B100-2x%5D%7D%3D%20-kt%20-%5Cfrac%7B1%7D%7B100%7D%5C%5C%5C%5Cor%20%5C%5C%5C%5C%20%5Cfrac%7B1%7D%7B%28100-2x%29%7D%20%3D%20kt%20%2B%20%5Cfrac%7B1%7D%7B100%7D)
after t = 7 minutes , 

Insert the above value x into
equation
to get k.


therefore plugging in the equation the above value of k

Let y = C
, calculate C:
y = 3x

amount of C formed in 28 mins
plug t = 28

therefore amount of C formed in 28 minutes is = 3x = 144.78 grams
C: 
y= 136.5 =137
The volume of the solution is given below which can be calculated using the molarity formula as 2.18 litres.
<h3>Define the molarity of a solution.</h3>
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.

Given data:
M= 0.420M
mass = 64.0 grams
Molar Mass= 74g/mol
To find:
The volume of solution=?
The calculation for a number of moles:
n= 
n= 
n= 0.91 moles
Molarity= 
V= 
V= 2.1768 litres
Thus, the volume of the solution is 2.18 litres.
Find more information about Molarity here:
brainly.com/question/26873446
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