Answer:
0.00212 kgs
Explanation:
one gram is equal to 0.001 kilograms
The change in the velocity = 4 m/s
Acceleration = 4 m/s²
<h3>Further explanation</h3>
Given
vo = initial velocity = 4 m/s
vf = final velocity = 8 m/s
t = 1 s
Required
The change in the velocity
Acceleration
Solution
the change in velocity =
![\tt vf-vo=8-4=4~m/s](https://tex.z-dn.net/?f=%5Ctt%20vf-vo%3D8-4%3D4~m%2Fs)
Acceleration = ratio of a change in velocity and the time
![\tt a=\dfrac{\Delta v}{t}= \dfrac{vf-vo}{t}](https://tex.z-dn.net/?f=%5Ctt%20a%3D%5Cdfrac%7B%5CDelta%20v%7D%7Bt%7D%3D%20%5Cdfrac%7Bvf-vo%7D%7Bt%7D)
Input the value :
![\tt a=\dfrac{4~m/s}{1~s}=4~m/s^2](https://tex.z-dn.net/?f=%5Ctt%20a%3D%5Cdfrac%7B4~m%2Fs%7D%7B1~s%7D%3D4~m%2Fs%5E2)
Answer:
a i think hope that helps
Answer:
Ionization energy of
is 54.4 eV.
Explanation:
![E_n=-13.6\times \frac{Z^2}{n^2}eV](https://tex.z-dn.net/?f=E_n%3D-13.6%5Ctimes%20%5Cfrac%7BZ%5E2%7D%7Bn%5E2%7DeV)
where,
= energy of orbit
n = number of orbit
Z = atomic number
Energy of n = 1 in an hydrogen like atom:
![E_1=-13.6\times \frac{2^2}{1^2}eV=-54.4 eV](https://tex.z-dn.net/?f=E_1%3D-13.6%5Ctimes%20%5Cfrac%7B2%5E2%7D%7B1%5E2%7DeV%3D-54.4%20eV)
Energy of n = ∞ in an hydrogen like atom:
![E_{\infty }=-13.6\times \frac{2^2}{\infty ^2}eV=0](https://tex.z-dn.net/?f=E_%7B%5Cinfty%20%7D%3D-13.6%5Ctimes%20%5Cfrac%7B2%5E2%7D%7B%5Cinfty%20%5E2%7DeV%3D0)
Ionization energy of
=
![E=E_{\infty }=E_1=0 - (-54.4 eV)=54.4 eV](https://tex.z-dn.net/?f=E%3DE_%7B%5Cinfty%20%7D%3DE_1%3D0%20-%20%28-54.4%20eV%29%3D54.4%20eV)