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Eduardwww [97]
3 years ago
14

What is the momentum of 70 kg runner traveling at 10 m/s?

Physics
2 answers:
Ivenika [448]3 years ago
8 0
700 kg m/s
Because momentum is mass times velocity
valentina_108 [34]3 years ago
5 0

Answer : The momentum of 70 kg runner is, 700 kg.m/s

Explanation :

Momentum : It is defined as the motion of a moving body. Or it is defined as the product of mass of velocity of an object.

Formula of momentum is:

p=mv

where,  

p = momentum  = ?

m = mass  = 70 kg

v = velocity  = 10 m/s

Now put all the given values in the above formula, we get:

p=(70kg)\times (10m/s)

p=700kg.m/s

Therefore, the momentum of 70 kg runner is, 700 kg.m/s

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According to the law of refraction, light passing from air into a piece of glass at an angle of 30 degrees will cause the light
pantera1 [17]

Answer:

bend toward the normal line

Explanation:

When light passes from a less dense to a more dense substance, (for example passing from air into water), the light is refracted (or bent) towards the normal.   In your question the light is moving from rarer to denser medium

4 0
3 years ago
Each of the space shuttle's main engines is fed liquid hydrogen bya high-pressure pump. Turbine blades inside the pump rotateat
kvasek [131]

Answer:

a) a= \frac{4 \pi^2 (0.02 m)^2}{0.00162 s}=9.74 \frac{m}{s^2}

b) k = \frac{9.8}{9.74}=1.006

Explanation:

Part a

For this case we can begin finding the period like this:

T= \frac{1}{w} =\frac{1}{617 rad/s}=0.00162 s

Then we know that the centripetal acceleration is given by:

a= \frac{v^2}{r}

And the velocity is given by:

v=\frac{2\pi r}{T}

If we replace this into the acceleration we got:

a = \frac{(\frac{2\pi r}{T})^2}{r}= \frac{4 \pi^2 r}{T^2}

And we can replace the values and we got:

a= \frac{4 \pi^2 (0.02 m)^2}{0.00162 s}=9.74 \frac{m}{s^2}

Part b

For this case we want to find a value of k such that:

a= k 9.8

Where a = 9.74, so then we can solve for k like this:

k = \frac{9.8}{9.74}=1.006

8 0
3 years ago
Assume your mass is 60 kg. The acceleration due to gravity is 9.8 m/s 2 . How much work against gravity do you do when you climb
Andre45 [30]

Answer:

W=1705.2 J

Explanation:

Given that

mass ,m= 60 kg

Acceleration due to gravity ,g= 9.8 m/s²

Height ,h= 2.9 m

As we know that work done by a force given as

W = F . d

F=force

d=Displacement

W=work done by force

Now by putting the values

F= m g (Acting downward  )

d= h  (Upward)

W= m g h    ( work done against the force)

W= 60 x 9.8 x 2.9 J

W=1705.2 J

Therefore the answer will be 1705.2 J.

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3 years ago
If the vertical axis and time on the horizontal axis if the speed is steadily increasing could the speef line ever become perfec
Phantasy [73]

A graph of real speed can have a section that's as steep as you want,
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Any vertical line on a graph, even it it's only a tiny tiny section, means
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It also means that the speed took no time to change from one value to
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8 0
3 years ago
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Elanso [62]

Answer:

about: 110.14 million mi

Explanation:

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Hope that was helpful.Thank you!!!

3 0
3 years ago
Read 2 more answers
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