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tankabanditka [31]
3 years ago
9

If an object is moving to the right and there is a net force acting on it to the left, what will happen to the object?

Physics
1 answer:
Ksju [112]3 years ago
7 0
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Plz help me with this ^^^
gogolik [260]
Assuming all the landmasses continue to move towards a sort of epicenter, large mountain ranges would appear in Africa and Europe.
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4 years ago
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If we compare and contrast electromagnetic waves with sound waves, all BUT one statement is true. That is A) sound waves require
ehidna [41]

its c electromagnetic waves must have a medium in which to travel, but sound waves can travel anywhere.

6 0
3 years ago
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A cart starts at x = +6.0 m and travels towards the origin with a constant speed of 2.0 m/s. What is it the exact cart position
Ira Lisetskai [31]

Answer:

At the origin (x' = 0 m)

Explanation:

Note: From the question, when the cart travels towards the origin, the magnitude of its exact position reduces with time.

The formula of speed is given as

S = d/t................. Equation 1

Where S = speed of the cart, d = distance covered by the cart over a certain time. t = time taken to cover the distance.

make d the subject of the equation,

d = St ................. Equation 2

Given: S = 2.0 m/s, t = 3.0 s

Substitute into equation 2

d = 2(3)

d = 6 m.

From the above, the cart covered a distance of 6 m in 3 s.

The exact position of the cart = Initial position-distance covered

x' = x-d............ Equation 3

Where x' = exact position of the cart 3 s later, x = initial position of the cart, d = distance covered by the cart in 3.0 s.

Given: x = +6.0 m, d = 6 m.

Substitute into equation 3

x' = +6-6

x' = 0 m.

Hence the cart will be at 0 m (origin) 3 s later

5 0
3 years ago
A kid walks 500 m North and then 300 m south.
Aleonysh [2.5K]

Explanation:

for the walking distance it did not matter in what direction the kid walked.

a. the distance of the walk is 500 + 300 = 800 m

b. the kid ended up 500-300=200 m north of the original point.

3 0
2 years ago
Car 1 has 7 times the mass of car 2, but only 0.6 as much kinetic energy. What is the ratio between the speeds of the two cars (
Sunny_sXe [5.5K]

Answer:0.29

Explanation:

Given

Car 1 has 7 times the mass of car 2

but 0.6 times the kinetic energy of car 2

suppose car 2 has the mass m and v_2 be the velocity

then car 1 has a mass of 7 m

Kinetic Energy of car 1

K_1=0.5\times 7m\times v_1^2-------1

Kinetic energy of car 2

K_2=0.5\times m\times v_2^2------2

divide 1 and 2 we get

\frac{K_1}{K_2}=\frac{7v_1^2}{v_2^2}

\frac{v_1}{v_2}=\sqrt{\frac{0.6}{7}}

\frac{v_1}{v_2}=0.29    

8 0
3 years ago
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