In
order to determine the mass of a standard baseball if it had the same density
(mass per unit volume) as a proton or neutron, we first determine the volume of
the baseball. The formula to be used is V_sphere = (4/3)*pi*r^3. In this case, the
radius r can be obtained from the circumference C, C = 2*pi*r. After plugging
in C = 23 cm to the equation, we get r = 3.6066 cm. The volume of the baseball
is then equal to 205.4625 cm^3.
Next,
take note of these necessary information:
Mass of a neutron/proton
= 10^-27 kg
Diameter of a
neutron/proton = 10^-15 m
Radius of a
neutron/proton = [(10^-15)/2]*100 = 5x10^-14 cm
<span>Thus,
the density, M/V of the neutron/proton is equal to 1.9099x10^12 kg/cm^3. Finally,
the mass of the baseball if it was a neutron/proton can be determined by
multiplying the density of the neutron/proton with the volume of the baseball. The
final answer is then a large value of 3.9241x10^14 kg.</span>
B. The meaning of 'atomos' according to Democritus in 450 BCE is indivisible.
<h3>
The building block of every matter</h3>
A Greek philosopher known as Democritus first thought of the existence of tiny particles that compose everything around us.
Democritus of Abdera, named the building blocks of matter atomos, meaning literally “indivisible.
Thus, the meaning of 'atomos' according to Democritus in 450 BCE is indivisible.
Learn more about atoms here: brainly.com/question/6258301
#SPJ1
Answer:
The super ball has a greater change in momentum.
Explanation:
50 g = 0.05 kg
The change in momentum of the clay ball going at 1m/s then stick (0m/s)
![\DeltaP_C = m_c v - 0 = 0.05*1 = 0.05 kgm/s](https://tex.z-dn.net/?f=%5CDeltaP_C%20%3D%20m_c%20v%20-%200%20%3D%200.05%2A1%20%3D%200.05%20kgm%2Fs)
As the superball change its velocity from 1m/s to -0.8m/s in opposite direction, its change in momentum would be
![\DeltaP_S = m_s(1 - (-0.8)) = 0.05*1.8 = 0.09 kgm/s](https://tex.z-dn.net/?f=%5CDeltaP_S%20%3D%20m_s%281%20-%20%28-0.8%29%29%20%3D%200.05%2A1.8%20%3D%200.09%20kgm%2Fs)
Since 0.09 > 0.05, the super ball has a greater change in momentum.
The answer would be D hope it helps and sorry if it is wrong. :)
We will use two definitions to solve this problem. The first will be given by the conservation of energy, whereby the change in kinetic energy must be equivalent to work. At the same time, work can be defined as the product between the force by the distance traveled. By matching these two expressions and clearing for the Force we can find the desired variable.
![W = KE_f-KE_i](https://tex.z-dn.net/?f=W%20%3D%20KE_f-KE_i)
![Fd = \frac{1}{2}mv_f^2-\frac{1}{2} mv_i^2](https://tex.z-dn.net/?f=Fd%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv_f%5E2-%5Cfrac%7B1%7D%7B2%7D%20mv_i%5E2)
Thus the force acting on the sled is,
![F = \frac{m}{2s} (v_f^2-v_i^2)](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bm%7D%7B2s%7D%20%28v_f%5E2-v_i%5E2%29)
Replacing,
![F = \frac{8}{2(2.5)}(6^2-4^2)](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B8%7D%7B2%282.5%29%7D%286%5E2-4%5E2%29)
![F = 32N](https://tex.z-dn.net/?f=F%20%3D%2032N)
Therefore the Force acting on the sled is 32N