To solve this problem we will apply the concept given by Pythagoras in the description of the lengths of the legs of a rectangular triangle and if equality against the square of the hypotenuse, that is
Here,
a, b = Legs of a triangle
c = Hypotenuse
According to the attached chart then we would have to
Substituting the given the lengths into the Pythagorean Theorem.
Therefore the distance x is 2830km.
Answer:
12.0 V
Explanation:
Data :
Potential difference due to a single charge (+Q), E = 3.0 V
The Electric potential for the system of charges is given as:
![E=\frac{1}{4\pi \epsilon_o}[\Sigma\frac{Q}{r}]](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B4%5Cpi%20%5Cepsilon_o%7D%5B%5CSigma%5Cfrac%7BQ%7D%7Br%7D%5D)
for single charge, E = 3.0 V = ![\frac{1}{4\pi \epsilon_o}[\frac{Q}{r}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%5Cpi%20%5Cepsilon_o%7D%5B%5Cfrac%7BQ%7D%7Br%7D%5D)
->eq(1)
And for 4 charges:
![E=\frac{1}{4\pi \epsilon_o}[4\frac{Q}{r}]](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B4%5Cpi%20%5Cepsilon_o%7D%5B4%5Cfrac%7BQ%7D%7Br%7D%5D)
-eq(2)
from eq(1) and (2) we have
E = 4 × 3.0 V = 12 V
Answer:
4 secs
Explanation:
The first step is to calculate the velocity
V= frequency × wavelength
= 500× 0.2
= 100
Therefore the time can be calculated as follows
= distance/velocity
= 400/100
= 4 secs
I think maybe possibly the answer could be a large mass
Answer:
R = 25 cm
Explanation:
We can solve this problem using the Archimedes principle that the magnitude of hydrostatic thrust equal to the weight of the liquid dislodged
Let's start by reducing all units is to the SI system
ρ liq = 1000 kg / m3 (water)
ρ body = 0.0950 g /cm³ (1 kg / 1000g) 10⁶ cm³ / 1m³) = 95 kg/m³
We use Newton's second law for this equilibrium case
B - F -W = 0
B = ρ liq g V
ρ = m / V
m = ρ V
W = ρbody g V
ρliq g V body - F - ρbody g Vbody =
Vbody g (ρliq - ρbody) = F
V body = F / g (ρliq - ρbody)
V body = 608 / [9.81 (1000 -95)
V body = 0.06855 m3
The volume of a sphere is
V = 4/3 pi R3
R =∛ ¾ V /π
R = ∛ ¾ 0.06855 /π
R = 0.254 m
R = 25 cm
