Since the sound travels from the submarine to the object AND back, it actually travelled 3625x2=7250m.
Speed of sound: 1450m/s
I need help with question 4
1 answer:
You might be interested in
Since the sound travels from the submarine to the object AND back, it actually travelled 3625x2=7250m.
Speed of sound: 1450m/s
Answer:
The runner's acceleration was
Explanation:
<u>Constant Acceleration Motion</u>
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
Solving for a:
The runner speeds up from vo=5 m/s to vf=9 m/s in t=4 seconds, thus:
The runner's acceleration was