Initial conditions:
m1 = 1.0 ; v1 = 5
m2 = 4.0 ; v2 = 0
In the case where the second object (sometimes called the target) is at rest the velocities after the condition are
v1' = v1* (m1-m2)/(m1+m2)
v2' = 2v1*m1/(m1+m2)
For this we get
v1' = 5*(-3)/5 = -3m/s (moving in the opposite direction as before at 3m/s
v2' = 2*5*(1)/5 = 2m/s in the same direction as the original ball was moving
you can see these directions by looking at the signs. The momenta also add to the initial momentum as required.
A. An object in motion will remain in motion unless acted upon by an outside force : The momentum of an object is constant unless an outside force acts on the object.
B. Force is defined as mass times acceleration : the rate of change of the momentum of a particle is proportional to the force F acting on it, hence the force is equal to <span>mass times acceleration.
C. </span>For every action there is an equal and opposite reaction : <span>to every action force there is an equal and opposite reaction force. </span>
Answer:
yeah I'm Pretty sure it's b
Answer:
2.4525 N
Explanation:
The earths gravity is 9.81 N/Kg
And so to work this out you would multiply 9.81 by 0.250 which equals to 2.4525N
Answer:
The distance from the North Pole to the equator is 
m.
Explanation:
Circumference of Earth = 40,000 km ......................(1)
Distance from the North Pole to the Equator is = 1/4th of the Circumference of Earth ...................... (2)
Let Distance from the North Pole to the Equator be d ,
the equation formed will be ,
d = 1/4 * Circumference of Earth ........(3)......... ( from equation 1 )
put the value of Circumference of Earth in equation (3),
d = 1/4 * 40,000 km
d = 10,000 km
converting km to m ,
d = 10,000 * 
m
d = 1 * 
m
The distance from the North Pole to the equator is m.
