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fiasKO [112]
4 years ago
9

Monochromatic light is incident on a grating that is 75 mm wide and ruled with 50,000 lines. the second-order maximum is seen at

32.5°. what is the wavelength of the incident light?
Physics
1 answer:
DIA [1.3K]4 years ago
4 0

Answer:

The wavelength of the incident light is \lambda = 400 nm

Explanation:

Given data

Distance between the sits

d = \frac{0.075}{50000}

d = 1.5 × 10^{-6} m

\theta = 32.5°

m = 2

We know that the wavelength of the incident light is given by

\lambda = \frac{d\sin \theta}{m}

Put all the value in above formula we get

\lambda = \frac{1.5 (\sin 32.5)}{2}×10^{-6}

\lambda = 4 × 10^{-7} m

\lambda = 400 nm

Therefore the wavelength of the incident light is \lambda = 400 nm

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